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Vika [28.1K]
2 years ago
10

in an effort to reach the store before it closed the motorist increase the speed of his car from 20 m per second to 60 meters pe

r second over a four second. What was the car's acceleration ​
Physics
1 answer:
Ber [7]2 years ago
7 0

Answer:

10

Explanation:

Givens

vi = 20 m/s

vf = 60 m/s

t = 4 second.

Formula

a = (vf - vi) / t

a = (60 - 20)/4

a = 40 / 4

a = 10 m/s^2

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Solve the following quadratic equations:2x² - 4x - 9 = 0 x₊ = 1 + √22/2Answersx_ = 1 - √22/2
Pavel [41]

The root quadratic equation of 2x^{2}  - 4x - 9 = 0 is x=\frac{2+\sqrt{22}}{2},\:x=\frac{2-\sqrt{22}}{2}

What is the formula used to calculate the quadratic equation?

To solve the quadratic equation use the formula of x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Find the quadratic equation by using the formula ?

On comparing with 2x^{2}  - 4x - 9 = 0

We get , a=2 , b=-4 , c=-9

D=b^{2} +7\\\\\\=(-4)^{2} +7*2*(-9)\\\\=-16-126\\\\=110

By using the formula,

For a quadratic equation of the formax^2+bx+c=0 the solutions are

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

X==\frac{-\left(-4\right)\pm \sqrt{\left(-4\right)^2-4\c* \:2\left(-9\right)}}{2\c* \:2}\\\\\sqrt{\left(-4\right)^2-4\cdot \:2\left(-9\right)}\\\\

Apply rule,

-(-a)=a\\\\=\sqrt{\left(-4\right)^2+4\cdot \:2\cdot \:9}\\\\

Apply exponent rule,

(-a)^{n} =a^{n} if n is even

(-4)^{2} =4^{2}

\sqrt{4^2+4\cdot \:2\cdot \:9}

Multiply the numbers :

4*2*9=72\\\\\sqrt{4^2+4\cdot \:2\cdot \:9}\\\\4^{2} =16\\\\=\sqrt{16+72}\\\\

Add the number  =\sqrt{88}

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A command economy<span> is a system where the government, rather than the free market, determines what goods should be produced, how much should be produced and the price at which the goods are offered for sale.</span>
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Answer:

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Explanation:

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A wheelbarrow is a good example of a second-class lever. True or False
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Answer:

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