Answer is: <span>percent ionization of aqueous acetic acid solution is 0.341%.
c(CH</span>₃COOH) = 1.55 M.
Ka(CH₃COOH) = 1.8·10⁻⁵.
Chemical reaction: CH₃COOH ⇄ CH₃COO⁻ + H⁺.
[CH₃COO⁻] = [H⁺] = x.
[CH₃COOH] = 1.55 M - x.
Ka = [CH₃COO⁻] · [H⁺] / [CH₃COOH].
1.8·10⁻⁵ = x² / (1.55 M - x).
Solve quadratic equation: x = 0.0053 M.
percent of ionization:
α = 0,0053 M ÷ 1.55 M · 100% = 0,341%
Answer:
i believe D Is the answer
Answer:The binding energy of the nitrogen nucleus is .
Explanation:
Atomic mass of the nitrogen, =14.00307 amu
Number of protons, Z = 7
Number of neutrons,N = Atomic mass - number of protons
=14.0037 - 7 =7.00307
Mass of proton ,
Mass of neutron,
Binding energy =
The binding energy of the nitrogen nucleus is .