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adell [148]
2 years ago
15

an atom of chlorine has an amount number of 17 and a mass number of 37. how many protons neutrons, and electrons are in the atom

?
Chemistry
1 answer:
Soloha48 [4]2 years ago
6 0

Answer: There are 20 protons neutrons in the atom

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3 years ago
A chemist prepares a sample of helium gas at a certain pressure, temperature and volume and then removes all but a fourth of the
cupoosta [38]

Answer:

The temperature must be changed to 4 times of the initial temperature so as to keep the pressure and the volume the same.

Explanation:

Pressure in the container is P and volume is V.

Temperature of the helium gas molecules =T_1

Molecules helium gas = x

Moles of helium has = n_1= \frac{x}{N_A}

PV = nRT (Ideal gas equation)

PV=n_1RT_1...[1]  

After removal of helium gas only a fourth of the gas molecules remains and pressure in the container and volume should remain same.

Molecules of helium left after removal = \frac{x}{4}

Moles of helium has left after removal = n_2= \frac{x}{4\times N_A}

PV=n_2RT_2...[2]

n_1RT_1=n_2RT_2

\frac{x}{N_A}\times T_1=\frac{x}{4\times N_A}\times T_2

T_1=\frac{T_2}{4}

T_2=4T_1

The temperature must be changed to 4 times of the initial temperature so as to keep the pressure and the volume the same.

6 0
4 years ago
What is the pressure in atm exerted by 2.48 moles of a gas in a 250.0 mL container at 58 degrees celsius
Dvinal [7]
Since the question manages to include moles, pressure, volume, and temperature, then it is evident that in order to find the answer we will have to use the Ideal Gas Equation:  PV = nRT (where P = pressure; V = volume; n = number of moles; R = the Universal Constant [0.082 L·atm/mol·K]; and temperature.

First, in order to work out the questions, there is a need to convert the volume to Litres and the temperature to Kelvin based on the equation:
         250 mL = 0.250 L
             58 °C = 331 K

Also, based on the equation   P = nRT ÷ V

⇒         P  = (2.48 mol)(0.082 L · atm/mol · K)(331 K)  ÷  0.250 L
⇒         P  =  (67.31  L · atm) ÷ 0.250 L
⇒         P  =  269.25 atm

Thus the pressure exerted by the gas in the container is  269.25 atm.
  


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