What type of reaction is: 4 Fe + 3 O2 → 2 Fe2O3
1 answer:
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Specif gravity = density of the material / density of water
density of the material = specific gravity * density of water
density of gold = 19.3 * 1 g/mL = 19.3 g/mL
density = mass / volume ==> Volume = mass / density
Volume = 0.4 kg * 1000 g/kg / 19.3 g/mL = 20.725 mL
Length of one side of the cube =![\sqrt[3]{20.725 {cm}^{3} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B20.725%20%7Bcm%7D%5E%7B3%7D%20%7D%20)
= 2.75 cm
Pass cm to inches
2.75 cm * 1 inch / 2.54 cm = 1.08 inch
density of the material = specific gravity * density of water
density of gold = 19.3 * 1 g/mL = 19.3 g/mL
density = mass / volume ==> Volume = mass / density
Volume = 0.4 kg * 1000 g/kg / 19.3 g/mL = 20.725 mL
Length of one side of the cube =
Pass cm to inches
2.75 cm * 1 inch / 2.54 cm = 1.08 inch
Answer:
11.6 mol O₂
Explanation:
- C₇H₁₆ + 11 O₂ → 7 CO₂ + 8 H₂O
In order to solve this problem we need to <u>convert moles of carbon dioxide (CO₂) into moles of oxygen gas (O₂)</u>. To do so we'll use a conversion factor containing the <em>stoichiometric coefficients</em> of the balanced reaction:
- 7.4 mol CO₂ *
= 11.6 mol O₂