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beks73 [17]
2 years ago
12

The volume of a gas is 450 mL when its pressure is 1.00 atm. If the temperature of the gas does not change, what is the pressure

when its volume is changed to 2.00 L?
Use P Subscript 1 Baseline V Subscript 1 = P Subscript 2 Baseline V Subscript 2.

0.225 atm
0.444 atm
2.25 atm
4.44 atm
Chemistry
2 answers:
posledela2 years ago
6 0

Answer:

0.225atm

Explanation:

got a 100 on the unit test

Delvig [45]2 years ago
3 0

Answer:

0.225 atm

Explanation:

v1=450ml÷1000=0.45l(1l=1000ml)

P1=1

v2=2.00l

p2=?

p1v1=p2v2

p2=p1v1/v2

=1×0.45/2

=0.225

so the answer is first one

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Answer:

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Explanation:

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Calculate the mass defect for the formation of phosphorus-31. The mass of a phosphorus-31 nucleus is 30.973765 amu. The masses o
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<u>Answer:</u> The mass defect for the formation of phosphorus-31 is 0.27399

<u>Explanation:</u>

Mass defect is defined as the difference in the mass of an isotope and its mass number.

The equation used to calculate mass defect follows:

\Delta m=[(n_p\times m_p)+(n_n\times m_n)]-M

where,

n_p = number of protons

m_p = mass of one proton

n_n = number of neutrons

m_n = mass of one neutron

M = mass number of element

We are given:

An isotope of phosphorus which is _{15}^{31}\textrm{P}

Number of protons = atomic number = 15

Number of neutrons = Mass number - atomic number = 31 - 15 = 16

Mass of proton = 1.00728 amu

Mass of neutron = 1.00866 amu

Mass number of phosphorus = 30.973765 amu

Putting values in above equation, we get:

\Delta m=[(15\times 1.00728)+(16\times 1.00866)]-30.973765\\\\\Delta m=0.27399

Hence, the mass defect for the formation of phosphorus-31 is 0.27399

8 0
3 years ago
The number 0.000402 expressed in scientific notation is
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Answer:

hope its help you

Explanation:

4.02 x 10-4

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