Ask question

Ask question

All categories

2 years ago

14

A horizontal force is used to pull a 5.0 kilogram cart at a constant speed of 5.0 m/s across the floor. The force of friction be

tween the cart and the floor is 10.0 newtons. What is the magnitude of the horizontal force along the handle of the cart?
5 N
10 N
15 N
20 N

1 answer:

AlekseyPX2 years ago

6 0

Answer:10N

Explanation:

You might be interested in

Which of the following adaptations best protects birds from bird catchers?

andrew-mc [135]

Wings to fly. Without flying, birds would be near defenseless.

5 0

2 years ago

Read 2 more answers

Plz help idk and it's due tomorrow

____ [38]

1) G. The continents are now farther apart. 2) A. P waves. They usually travel 60% faster than S waves. 3) H. A hot spot caused the Hawaiian Islands to form.

7 0

2 years ago

Read 2 more answers

A 5.30kg block hangs from a spring with a spring constant 1700 N/m. The block is pulled down 4.50cm from the equilibrium positio

Andru [333]

To solve this problem it is necessary to apply the concepts related to the frequency in a spring, the conservation of energy and the total mechanical energy in the body (kinetic or potential as the case may be)

PART A) By definition the frequency in a spring is given by the equation

$f = \frac{1}{2\pi} \sqrt{\frac{k}{m}}$

Where,

m = mass

k = spring constant

Our values are,

k=1700N/m

m=5.3 kg

Replacing,

$f = \frac{1}{2\pi} \sqrt{\frac{1700}{5.3}}$

$f=2.85 Hz$

PART B) To solve this section it is necessary to apply the concepts related to the conservation of energy both potential (simple harmonic) and kinetic in the spring.

$\frac{1}{2}kA^2 = \frac{1}{2}mv^2 + \frac{1}{2} kY^2$

Where,

k = Spring constant

m = mass

y = Vertical compression

v = Velocity

This expression is equivalent to,

$kA^2 =mV^2 +ky^2$

Our values are given as,

k=1700 N/m

V=1.70 m/s

y=0.045m

m=5.3 kg

Replacing we have,

$1700*A^2=5.3*1.7^2 +1700*(0.045)^2$

Solving for A,

$A^2 = \frac{5.3*1.7^2 +1700*(0.045)^2}{1700}$

$A ^2 = 0.011035$

$A=0.105 m \approx 10.5 cm$

PART C) Finally, the total mechanical energy is given by the equation

$E = \frac{1}{2}kA^2$

$E=\frac{1}{2}1700*(0.105)^2$

$E= 9.3712 J$

3 0

2 years ago

A volleyball is served at a speed of 8 / at an angle 35° above the horizontal. What is the speed of the ball when received by th

bezimeni [28]

The speed of the ball is how hard u hit it

7 0

1 year ago

A car with a constant velocity of 22 m/s is driven for 6.8 s. How far did it travel? (v =∆ d/∆t)

Genrish500 [490]

Answer:

C. 150 m

Explanation:

22 m/s x 6.8 = 149.6

3 0

2 years ago