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3 years ago

If it takes 150 n of force to accelerate an object at 30 m/s what is the mass of the object

1 answer:

3 0

F = ma.

Note Force should be = 150 N. Acceleration = 30 m/s2 ( Am presuming for your question you meant to write 30m/s2 and not 30m/s as you wrote)

150 = m ( 30)

150/30 = m.

5 = m

Mass of the object = 5 Kg.

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Why does a geostationary satellite must orbit around Earth's equator, rather than in some other orbit (such as around the poles)

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Answer:

A satellite on non-equatorial orbit would show daily motion even if its period is exactly 1 sidereal day.

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2 years ago

Two facing surfaces of two large parallel conducting plates separated by 8.5 cm have uniform surface charge densities such that

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Answer:

positive plate

E = 5.764 KV / m

W = 490eV or 7.85 * 10^-17 J

E_p = 4.74 *10^(-12) eV

E_k = 490 eV

Explanation:

part a

The potential difference between two plates = 490 V

Distance between two plates = 8.5 cm

Answer: The positive plate is at higher potential because of convention.

part b

Electric Field between the plates

E = V / d

E = 490 / 0.085 = 5.764 KV / m

Answer: Electric Field between the plates E = 5.764 KV / m

part c

Work done by electric field

W = V*q

W = 490 * 1.602*10^-19

W = 7.85 * 10^-17 J

or W = 490 eV

Answer: Work done by electric field W = 490eV or 7.85 * 10^-17 J

part d

Potential Energy of an electron gained:

E_p = m_e * g * d / (1.602*10^-19)

E_p = 9.109*10^-31* 9.81 * 0.085 / (1.602*10^-19)

E_p = 4.74 *10^(-12) eV

Very very small E_p approximately 0

Answer: Potential Energy of an electron gained E_p = 4.74 *10^(-12) eV or 0.

part e

Kinetic Energy of an electron gained:

W - E_p = E_k

E_k = 490eV - 4.74*10^(-12)eV

E_k = 490 eV

Answer: Kinetic Energy of an electron gained E_k = 490 eV

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3 years ago

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Answer:

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c=same explanation as a

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