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Lorico [155]
3 years ago
13

2. What is the feather's initial velocity (before it is dropped) in m/s?

Physics
1 answer:
Dmitrij [34]3 years ago
7 0

Answer: 0

Explanation: Initial velocity is 0.

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You drive a car east on the highway at 26 m/s. Another car passes you moving east traveling at 32 m/s. How fast do you view the
tamaranim1 [39]

The speed of the car passing you is 6 m/s while car is moving 6 m/s behind the car.

<h3>Relative velocity of the car</h3>

The speed of the car passing you is determined by applying relative velocity principle as shown below;

Vr = Va - Vb

Vr = 26 m/s - 32 m/s

Vr = -6 m/s

Thus, the speed of the car passing you is 6 m/s while car is moving 6 m/s behind the car.

Learn more about relative velocity here: brainly.com/question/17228388

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2 years ago
Automotive technology
viktelen [127]

lol what is this question

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How does the amount of atmosphere affect what color the sky appears to be?
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The atmosphere creates a cover over the earth preventing us from seeing space and it’s natural color and the light that is created by the sun reflected on the ocean creates the color that the sky appears to be blue
3 0
3 years ago
What is the minimum coefficient of friction needed for a frightened driver to take the same curve at 20.0 km/h?
Tanya [424]

Answer:

The minimum coefficient of friction is 0.22

Explanation:

Suppose If a car takes a banked curve at less than the ideal speed, friction is needed to keep it from sliding toward the inside of the curve.

We need to calculate the ideal speed to take a 85 m radius curve banked at 15°.

Given that,

Radius = 85 m

Angle = 15°

Speed = 20 km/h

We need to calculate the ideal speed

Using formula of speed

\tan\theta=\dfrac{v^2}{rg}

v=\sqrt{rg\tan\theta}

Put the value into the formula

v=\sqrt{85\times9.8\tan15}

v=14.9\ m/s

We need to calculate the minimum coefficient of friction

Using formula for coefficient of friction

v^2=\dfrac{rg(\sin\theta-\mu\cos\theta)}{\mu\sin\theta+\cos\theta}

Put the value into the formula

(5.55)^2=\dfrac{85\times9.8(\sin15-\mu\cos15)}{\mu\sin15+\cos15}

\dfrac{30.8025}{85\times9.8}=\dfrac{0.2588-\mu0.966}{\mu0.2588+0.966}

0.9754462\ mu-0.223541=0

\mu=\dfrac{0.223541}{0.9754462}

\mu=0.22

Hence, The minimum coefficient of friction is 0.22

3 0
2 years ago
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