The upward force exerted on the board by the support is mathematically given as
Fu= 764.8 N
<h3>What is the upward force exerted on the board by the support?</h3>
Generally, the equation for is mathematically given as
Considering that the Net Force on the system is null
The weight of the children plus the weight of the board equals the upward force imposed on the support.
The upward force
Fu= 440 + 272 + 52.8 N
Fu= 764.8 N
In conclusion, he upward force exerted on the board by the support
Fu= 764.8 N
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The net force on the block acting perpendicular to the incline is
∑ <em>F</em> = <em>n</em> - <em>w</em> cos(29.4°) = 0
where <em>n</em> is the magnitude of the normal force and <em>w</em> = <em>m g</em> is the weight of the block.
The equation itself comes from splitting up the forces acting on the block into components pointing parallel or perpendicular to the incline. The only forces acting on the block in the perpendicular direction are the normal force and the perpendicular component of the block's weight.
Solve for <em>n</em> :
<em>n</em> = <em>m g</em> cos(29.4°)
<em>n</em> = (6 kg) (9.80 m/s²) cos(29.4°)
<em>n</em> ≈ 51.2 N
I know that the relationship between altitude and atmospheric density is that the higher the altitude, the lesser the density, and the lower the altitude the higher the density. Lower density float to the top, and higher density is 'heavy' so it comes down
2,000 j(apex)
i hope this was right
Whether a line is "steep" or "shallow" depends on the slope of the line. In the equation y=mx+b, m is the slope. In your first equation, 1/2x+4, the slope would be 1/2 which means there is 1 increase in the vertical, or y, value for each 2 increases in the horizontal, or x value. This line would be shallow.
