The same power (1.9×10^4 watts) gets diminished by Inverse square law
<span>(ratio of distances)² </span>
<span>= (138/70000)² </span>
<span>= 3.886506 X 10^-6 . </span>
<span>This is the diminution factor for the given sensitivity of the telescope. But at 3.8865 millionth below the sensitivity its is far below detection; it needs to be enhanced by collecting the energy over an area so many times more (by an aperture multiplied by same factor) </span>
<span>1/[3.886506 X 10^-6] = 257298.88 </span>
<span>In other words the diameter should have the ratio of square root of this </span>
<span>(70000/138). </span>
<span>This multiplied by 300m dish gives </span>
<span>300 X (70000/138) = 152173.913 m = 152.1739 km. </span>
<span>This should be the aperture of the new telescope for detecting the signal.</span>
Answer:
The distance of the image produced by the concave mirror is 11.27 cm.
Explanation:
Given that,
Focal length = 8.40 cm
Distance between object and plane mirror = 11.0 cm
Distance between plane mirror and concave mirror = 22.0 cm
We need to calculate the object distance
We need to calculate the distance of the image
Using formula of distance of the image
Where, u = Object distance
f = focal length
Put the value into the formula
Hence, The distance of the image produced by the concave mirror is 11.27 cm.
The answer is A. They are both processes in which water is changed into water vapor.
Answer:
11.48 degree N of W
Explanation:
We are given that
Wind velocity=km/h
Because wind is blowing towards south
Air speed=
Because the captain want to move with air speed in west direction.
x component of relative velocity=-212 km/h
y-Component of relative velocity=-43km/h
Direction=
N of W
Hence, the direction in which the pilot should set her course to travel due west=11.48 degree N of W