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WITCHER [35]
2 years ago
8

- 4/9 times - 5/8 in fractions.

Mathematics
1 answer:
omeli [17]2 years ago
5 0

Answer:

5/8 x 4/9 = 20/72 as simplified as 5/18 in fraction form. 5/8 x 4/9 = 0.2778 in decimal form.

Step-by-step explanation:

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The sum of three consecutive numbers is -12. Find the sum of the integers?
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Answer: -3, -4, -5 are the integers

Step-by-step explanation: I don't get what you mean in this problem. You said the sum was -12 but then you are asking for the sum again? Do you want the integers? If so they are -3 -4 and -5 and if you want the sum then it is -12

I hope this helps and brainliest would be appreciated

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Can someone help me with these two? Please
avanturin [10]
For 16/18 it would be 8/9
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A mapping diagram showing a relation, using arrows, between input and output for the following ordered pairs: (negative 3, negat
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Answer:

  {x | x = –5, –3, 1, 2, 6}

Step-by-step explanation:

The domain is the list of first-values of the ordered pairs:

   {x | x = –5, –3, 1, 2, 6}

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One end of a line segment has the coordinates (-6,2). If
CaHeK987 [17]

Answer:

The coordinates of the other end is (16,2)

Step-by-step explanation:

Given

End 1: (-6,2)

Midpoint: (5,2)

Required

Find the coordinates of the other end

Let Midpoint be represented by (x,y);

(x,y) = (5,2) is calculated as thus

(x,y) = (\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})

So

x = \frac{x_1 + x_2}{2} and y = \frac{y_1 + y_2}{2}

Where (x_1,y_1) = (-6,2) and (x,y) = (5,2)

So, we're solving for (x_2,y_2)

Solving for x_2

x = \frac{x_1 + x_2}{2}

Substitute 5 for x and -6 for x₁

5 = \frac{-6 + x_2}{2}

Multiply both sides by 2

2 * 5 = \frac{-6 + x_2}{2} * 2

10 = -6 + x_2

Add 6 to both sides

6 + 10 = -6 +6 +  x_2

x_2 = 16

Solving for y_2

y = \frac{y_1 + y_2}{2}

Substitute 2 for y and 2 for y₁

2 = \frac{2 + y_2}{2}

Multiply both sides by 2

2 * 2 = \frac{2 + y_2}{2} * 2

4 = 2 + y_2

Subtract 2 from both sides

4 - 2 = 2 - 2 + y_2

y_2 = 2

(x_2,y_2) = (16,2)

Hence, the coordinates of the other end is (16,2)

3 0
3 years ago
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