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Korolek [52]
3 years ago
12

An object with a mass of 2.00 kg is placed at the end of a spring, having a spring constant of 180.0 N/m. The spring is then com

pressed 0.890 m. What is the maximum velocity of the mass?
Physics
1 answer:
s2008m [1.1K]3 years ago
8 0

Answer:

the velocity of the mass is 8.44 m/s

Explanation:

Given;

mass of the object, m = 2 kg

spring constant, k = 180 N/m

extension of the spring, x = 0.89 m

The maximum velocity of the mass is calculated as follows;

By the principle of conservation of energy;

Elastic potential energy = kinetic potential energy

¹/₂kx² = ¹/₂mv²

kx² = mv²

v^2 = \frac{kx^2}{m} \\\\v = \sqrt{\frac{kx^2}{m} } \\\\v = \sqrt{\frac{180 \times 0.89^2}{2} }\\\\v = 8.44 \ m/s

Therefore, the velocity of the mass is 8.44 m/s

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Which best describes the law of conservation of mass?
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Define speed and what is it’s SI unit.
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8 0
3 years ago
A city bus travels 6 blocks east and 8 blocks north. Each block is 100 m long. If the bus travels this distance in 15 minutes, w
nexus9112 [7]

Answer:

The average speed of the bus, v = 1.55 m/s

Explanation:

Given that,

Number of blocks traveled by bus towards east = 6

Number of blocks traveled by bus towards north = 8

Length of each block = 100 m

Distance traveled by bus towards east 6 x 100 = 600 m

Distance traveled by bus towards north 8 x 100 = 800 m

The total distance traveled, d = 600 + 800 = 1400

Time taken by the bus to travel is, t = 15 minutes

The velocity is given by the formula

                                  v = d/t  m

Substituting the values in the above equation

                                   v = 1400 m /(15 x 60) s

                                      = 1.55 m/s

Hence, the average speed of the bus, v = 1.55 m/s

6 0
3 years ago
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