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ira [324]
3 years ago
13

What is the effect of this

Chemistry
1 answer:
Lina20 [59]3 years ago
3 0

Answer:

Waves transfer energy from one place to another without transferring matter. Wave motion (the movement of waves) can be shown by the vibrations of a spring or by water waves.

<u><em>Hope this helps!! have a good day! :)</em></u>

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A liquid is considered an acid if it has a lot of
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H+ ions
That's the answer to your question
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In the turbine of a nuclear power plant, the mechanical energy is converted
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It would be Thermal energy
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Read 2 more answers
Ni-cad (nickel–cadmium) batteries have a slightly lower cell potential than the common alkaline value of 1.5 v normally used in
Lorico [155]
The half-reaction are:

Cd ---> Cd(OH)₂
The oxidation number of Cd changed from 0 to +2. So, the number of mol electron transferred here is 2.

NiO(OH) --> Ni(OH)₂
The oxidation number of Cd changed from +3 to +2. So, the number of mol electron transferred here is 1.

Now, the greatest common factor would be 2. So, we use n=2 for the formula for ΔG°. F is Faraday's constant equal to 96,485 J/mol e.

ΔG° = nFE° = (2)(96,485)(1.5) =<em> 289,455 J</em>


6 0
3 years ago
69. Sequencing Arrange these hydrates in order of
Kobotan [32]

In order of  increasing percent water content:CoCl₂.6H₂O, Ba(OH)₂.8H₂O, MgSO₄.7H₂O

<h3>Further explanation</h3>

\tt \%element=\dfrac{Ar~element}{MW~compound}\times 100\%

CoCl₂.6H₂O.MW=237.90 g/mol

6H₂O MW = 6.18=108 g/mol

\tt \%H_2O=\dfrac{108}{237.9}\times 100\%=45.4\%

MgSO₄.7H₂O.MW=246.48 g/mol

MW 7H₂O = 7.18=126 g/mol

\tt \%H_2O=\dfrac{126}{246.48}\times 100\%=51.1\%

Ba(OH)₂.8H₂O MW=315.48 g/mol

MW 8H₂O = 8.18=144 g/mol

\tt \%H_2O=\dfrac{144}{315.48}\times 100\%=45.6\%

4 0
3 years ago
Calculate the work done when an ideal gas expands isothermally and reversibly in a piston and cylinder assembly for expansion of
pantera1 [17]

Answer:

W=5743.1077\ J

Explanation:

The expression for the work done is:

W=RT \ln \left( \dfrac{P_1}{P_2} \right)

Where,

W is the amount of work done by the gas

R is Gas constant having value = 8.314 J / K mol

T is the temperature

P₁ is the initial pressure

P₂ is the final pressure

Given that:

T = 300 K

P₁ = 10 bar

P₂ = 1 bar

Applying in the equation as:

W=8.314\times 300 \ln \left( \dfrac{10}{1} \right)

W=300\times \:8.314\ln \left(10\right)

W=2.30258\times \:2494.2

W=5743.1077\ J

5 0
3 years ago
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