Lead (II) acetate trihydrate is the systematic name for the formula Pb(C₂H₃O₂)₂ . 3H₂O.
<h3>What is Molecular Formula ?</h3>
The chemical formula that gives total number of atoms of each element in one molecule of a compound is called Molecular Formula.
<h3>What is Oxidation State ?</h3>
Oxidation state is also known as oxidation number. It is defined as the atom is equal to the total number of electrons which have been removed from the element in order to form chemical bond with other atom.
Now find the oxidation state of Pb in Pb(C₂H₃O₂)₂ .3H₂O
Assume the oxidation state of Pb in Pb(C₂H₃O₂)₂ .3H₂O be x
x + 2 × (-1) + 3 × 0 = 0
x - 2 + 0 = 0
x = 2
Oxidation state of Pb is +2 or (II)
Thus from the above conclusion we can say that The systematic name for the formula Pb(C₂H₃O₂)₂ .3H₂O is Lead (II) acetate trihydrate.
Learn more about the Molecular Formula here: brainly.com/question/15960587
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Answer is: a beaker contains <span>
heterogeneous mixture.
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A heterogeneous mixture<span> have compounds that remain separate in the sample.</span>
Heterogeneous
mixture is not uniform in composition (in this mixture different sand and small pebbles), but proportions of its components (in this
mixture particles of different colors and size) vary throughout
the sample.
The answer is H—F. Fluorine is the most electronegative of the four halogens (and, in fact, of all the elements), so it does the best job of gathering the shared electrons to itself. Therefore, the bond with F is the most polar
Answer:The Law of Conservation of Mass simply states that the total amount of mass should not change in a chemical reaction that is isolated (no other objects can enter the reaction). The total mass of the reactants must be equal to the total mass of the products. Thus, the correct estimate of the amount of oxygen used in the interaction is the difference between 133 g and 29 g.
Explanation: I hope this helped!
The POH of a 2.70 x10^-11 solution of lithium hydroxide(LiOH) is 10.6
calculation
POH= -log (OH-)
write the equation for dissociation of LiOH
LiOh---> Li^+(aq) + OH-(aq)
from the equation above the ratio LiOH: OH is 1:1 therefore the concentration of OH- =2.70 x10 ^-11
that is - log (2.70 x10^-11) = 10.6
