2 years ago

A helium balloon with an internal pressure of 1.25 atm and a volume of 3.50 L at 25.00 C

1 answer:

6 0

Using the combined gas law ((P1•V1)/T1) = ((P2•V2)/T2), you get ((1.25atm•3.5L)/298K) = ((0.800atm•V2)/243K). Solving for V2 you get 4.46L.

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mario62 [17]

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eimsori [14]

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Stels [109]

Number of charge = 5018 C

<h3>Further explanation</h3>

Given

1000 C of charge for x grams of copper

Required

Number of charge

Solution

Faraday's Law :

$\tt W=\dfrac{e.i.t}{96500}\\\\W=\dfrac{e.Q}{96500}$

For 1000 C, W = x grams

$\tt x=\dfrac{1000.e}{96500}=0.0104e$

For 5x grams :

$\tt 5x=\dfrac{e.Q}{96500}\\\\5\times 0.0104e=\dfrac{e.Q}{96500}\\\\Q=\dfrac{96500\times 5\times 0.0104e}{e}=5018~C$

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3 years ago