A helium balloon with an internal pressure of 1.25 atm and a volume of 3.50 L at 25.00 C

1 answer:

6 0

Using the combined gas law ((P1•V1)/T1) = ((P2•V2)/T2), you get ((1.25atm•3.5L)/298K) = ((0.800atm•V2)/243K). Solving for V2 you get 4.46L.

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<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

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By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

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<h3>Moles of CaO required</h3>

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$moles of CaO=\frac{2 moles of Ca(OH)_{2}x1 mol of CaO }{1 mole of Ca(OH)_{2}}$