Answer:
Probability that the sample mean comprehensive strength exceeds 4985 psi is 0.99999.
Step-by-step explanation:
We are given that a random sample of n = 9 structural elements is tested for comprehensive strength. We know the true mean comprehensive strength μ = 5500 psi and the standard deviation is σ = 100 psi.
<u><em>Let </em></u>
<u><em> = sample mean comprehensive strength</em></u>
The z-score probability distribution for sample mean is given by;
Z =
~ N(0,1)
where,
= population mean comprehensive strength = 5500 psi
= standard deviation = 100 psi
The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.
Now, Probability that the sample mean comprehensive strength exceeds 4985 psi is given by = P(
> 4985 psi)
P(
> 4985 psi) = P(
>
) = P(Z > -15.45) = P(Z < 15.45)
= <u>0.99999</u>
<em>Since in the z table the highest critical value of x for which a probability area is given is x = 4.40 which is 0.99999, so we assume that our required probability will be equal to 0.99999.</em>
Answer:
it is D. the murmurs of a group
Step-by-step explanation:
Answer:
Mean= 5.70
Standard deviation= 0.132
Step-by-step explanation:
For the distribution of sample mean:
Mean of the sampling distrubution = \mu = 5.70
Standard deviation of the sampling distrubution = sigma/sqrt{n} = 1.7201 /sqrt{170} = 0.132
y = ax^2
If the absolute value of a is <1 the graph is wider than when a = 1
If the absolute value of a is >1 the graph is narrow than when a = 1
The only function that fits that description is
y = 2x^2
Answer:
The correct answer is the second option