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vampirchik [111]
3 years ago
11

Assuming the input of energy continues for another 2.5 seconds, where will the particle be?

Physics
1 answer:
VladimirAG [237]3 years ago
3 0
Well i had the same question on my test, and when the graph in 2.5 seconds goes up from the equilibrium it reaches a positive maximum, so that would be your answer. 

b. positive maximum 
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Complete Question

The complete question is shown on the first uploaded image

Answer:

The workdone is  W = -177.275J

Explanation:

From the question we are told that

      The initial Volume is  Vi = 0.160 L

      The final volume is  V_f = 0.510L

      The external pressure is  P = 5.00 \ atm

Generally the change in volume is

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           \Delta V = 0.510 -0.160

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Generally workdone is mathematically represented as

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W is negative because the working is done on the environment by the system which is indicated by volume increase

     Substituting values

                W = - 5* 0.350

                    = -1.75 \ L \ \cdot atm

Now  1 \  L \cdot atm = 101.3J

  Therefore  W = -1.75* 101.3

                          = -177.275J

   

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