A transformer is used to light a lamp rated 40w, 240v from a 400v A.C supply. Calculate:
1 answer:
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Answer:
<em>work done in pumping the entire fuel is 466587 J</em>
<em></em>
Explanation:
weight of the gasoline per volume = 6600 N/m^3
diameter of the tank = 3 m
length of the tank = 2 m
height of the tractor tank above the top of the tank = 5 m
work done in pumping fuel to this height = ?
First, we find the volume of the fuel
since the tank is cylindrical,<em> we assume that the fuel within also takes the cylindrical shape.</em>
<em>Also, we assume that the fuel completely fills the tank.</em>
volume of a cylinder =
where r = radius = diameter ÷ 2 = 3/2 = 1.5 m
volume of the cylinder = 3.142 x x 2 = 14.139 m^3
we then find the total weight of the fuel in Newton
total weight = (weight per volume) x volume
total weight = 6600 x 14.139 = 93317.4 N
work done = (total weight of the fuel) x (height through which the fuel is pumped)
work done in pumping = 93317.4 x 5 = <em>466587 J</em>
Answer:
0.30581
0.24464
Explanation:
= Coefficient of static friction
= Coefficient of kinetic friction
= 75 N
= 60 N
Normal force
Frictional force
The coefficient of static friction is 0.30581
Kinetic force
The coefficient of kinetic friction is 0.24464