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3 years ago

What is the equation of a line that is perpendicular to -x+3y=9 and passes through point (-3,2)

Mathematics

1 answer:

Lynna [10]3 years ago

8 0

Answer:

The perpendicular line would be y = -3x - 7

Step-by-step explanation:

To find the equation of the line, we first need to solve the original line for y.

-x + 3y = 9

3y = x + 9

y = 1/3x + 3

Now we know the slope of the original line to be 1/3. Since perpendicular lines have opposite and reciprocal slope, we know the new line to have a slope of -3. We can then use that along with the given point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - 2 = -3(x + 3)

y - 2 = -3x - 9

y = -3x - 7

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2 years ago

Write an equation for the nth term of the arithmetic sequence: 15,28,41 ....

11111nata11111 [884]

Answer:

The equation for the nth term of the given arithmetic sequence is: $\mathbf{a_n=13n+22}$

Step-by-step explanation:

We need to write an equation for the nth term of the arithmetic sequence:

15,28,41 ....

The equation for arithmetic sequence is: $a_n=a_1+(n-1)d$

Where $a_n$ is the nth term, $a_1$ is first term and d is common difference

In the given sequence we have:

a₁ = 15

a₂ = 28

We can find common difference using the formula:

$a_n=a_1+(n-1)d\\Put\: n=2, a_2=28\: and\: a_1=15\\a_2=a_1+(2-1)d\\28=15+d\\d=28-15\\d=13$

So, the common difference d is 13

Now, equation for nth term will be:

$a_n=a_1+(n-1)d\\Put\:a_1=15, d=13\\a_n=15+(n-1)13\\Solving:\\a_n=15+13n-13\\a_n=13n+2$

So, the equation for the nth term of the given arithmetic sequence is: $\mathbf{a_n=13n+22}$

where n=1,2,3..

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2 years ago

Find the missing length indicated. х 12 9 X = units

madam [21]

Answer:

Step-by-step explanation:

9/12=12/x

x=16

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2 years ago

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The partial product of 4.6×3.5 is 16.1

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Answer:

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Step-by-step explanation:

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