What is the equation of a line that is perpendicular to -x+3y=9 and passes through point (-3,2)

Mathematics

1 answer:

Lynna [10]3 years ago

8 0

Answer:

The perpendicular line would be y = -3x - 7

Step-by-step explanation:

To find the equation of the line, we first need to solve the original line for y.

-x + 3y = 9

3y = x + 9

y = 1/3x + 3

Now we know the slope of the original line to be 1/3. Since perpendicular lines have opposite and reciprocal slope, we know the new line to have a slope of -3. We can then use that along with the given point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - 2 = -3(x + 3)

y - 2 = -3x - 9

y = -3x - 7

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andreev551 [17]

Answer:

$-10+i\sqrt{2}$

Step-by-step explanation:

One is given the following expression:

$\sqrt{4}-\sqrt{-98}-\sqrt{144}+\sqrt{-128}$

In order to simplify and solve this problem, one must keep the following points in mind: the square root function ( $\sqrt{}$ ) is a way of requesting one to find what number times itself equals the number underneath the radical sign. One must also remember the function of taking the square root of a negative number. Remember the following property: ( $\sqrt{-1}=i$ ). Simplify the given equation. Factor each of the terms and rewrite the equation. Use the square root property to simplify the radicals and perform operations between them.