3 years ago

A baker needs 8 1/2

Mathematics

1 answer:

ankoles [38]3 years ago

3 0

Answer:

Step-by-step explanation:

OKAY, IM DOING A TEST WITH THIS QUESTION IM PRETTY SURE U NEED TO 4/23+5/14 AND WHATEVER THAT = YOU THEN SUBTRACT 8/12 AND I FORGOT HOW TO DO THE DARN ADDING-

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jarptica [38.1K]

Answer:

1. 6/9

2. 6/3

3. 3/6

4. 9/6

5. 3/9

1. 8/12

2. 3/7

3. 5/3

4. 12/15

5. 20/25

Step-by-step explanation:

You can turn a ratio from #:# into #/# so if the ratio was 3:9 the fraction form would be 3/9.

4 0

2 years ago

Help on college algebra, question is on the picture!

kodGreya [7K]

$\frac{7x+1}{x-2} + \frac{2}{x} = \frac{-4}{ x^{2} -2x}$ is given
here , $\frac{7x+1}{x-2} + \frac{2}{x} = \frac{-4}{ x^{2} -2x}$
or, $\frac{7x^{2} +x +2x-4 }{x(x-2)} = \frac{-4}{ x^{2} -2x}$
or, $\frac{7 x^{2} +3x-4}{ x^{2} -2x} = \frac{-4}{ x^{2} -2x}$
or,7x²+3x-4=-4
or,7x²+3x=0
or,x(7x+3)=0
Either,x=0| Or,7x+3=0
|or,7x=-3
|or,x= $\frac{-3}{7}$
So , the solution set is S={0,- $\frac{3}{7}$ }