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drek231 [11]
3 years ago
15

What is the point slope form of the line with slope 25 that passes through the point (−4, −7)?

Mathematics
1 answer:
Arisa [49]3 years ago
6 0

Answer:

Option A: y+7 = 25(x+4) is the correct answer.

Step-by-step explanation:

The point-slope form of an equation of a line is given by:

y-y_1 = m(x-x_1)

Here:

m is the slope of the line

(x_1,y_1) are the coordinates of the point from which the line passes.

Now looking at the given question:

m = 25\\(x_1,y_1) = (-4,-7)

Putting the values in the general form of point-slope form of equation of line

y-(-7) = 25\{x-(-4)\}\\y+7 = 25(x+4)

Hence, the point-slope form of given line is:

y+7 = 25(x+4)

Observing the option given, it can be concluded that Option A: y+7 = 25(x+4) is the correct answer.

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Read 2 more answers
Two forces with magnitudes of 150 and 75 pounds act on an object at angles of 30° and 150°, respectively. Find the direction and
kompoz [17]
Answer:

Magnitude: 121.35 pounds

Direction: 21.64°

Explanation:

1) Decompose each force into its x - y components.

2) Force 1, F1: 140 pounds at angle of 30°

x-component: F1,x

F1, x = F1 *cos(30°) = 140 pounds * cos(30°) = 121.24 pounds

y-component: F1,y

F1,y = F1 * sin(30°) = 140 pounds * sin(30°) = 70 pounds.

3) Force 2, F2: 75 poounds at 150°

x-component: F2,x

F2,x = F2 * cos(150°) = 75 pounds * cos(150°) = - 64.95 pounds

y-component: F2,y

F2,y = F2 * sin(150°) = 75 pounds * sin(150°) = 37.5 pounds

4) Resultant Force, Fr

x-component: Fr,x

Fr,x = F1,x + F2,x = 121.24 pounds - 64.95 pounds = 56.29 pounds

y-component: Fr,y

Fr,y = F1,y + F2,y = 70 pounds + 37.5 pounds = 107.5 pounds

4.1) magnitude

|Fr| = √ [ (56.29 pouns)^2 + (107.5 pounds)^2 ] = 121.35 pounds.

4.2) direction

tan(α) = Fr,y / Fr,3 = 56.29 pounds / 107.5 pouns = 0.5236

=> α = arctan(0.5236) = 27.64 °


5 0
3 years ago
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