A=adult pay
c=child pay
3a+4c=83
2a+3c=59
subtract
a+c=24
2a+2c=48
2a+3c-2a-2c=59-48
c=11
a=24-11=13
price of adult ticket=13$
price of child's ticket=$11
Answer:
No Solutions.
Step-by-step explanation:
I will solve your system by substitution.
3y−3=3x; −3x+3y=−57
Step: Solve 3y−3=3x for y:
3y−3+3=3x+3 (Add 3 to both sides)
3y=3x+3
(3y/3=3x+3)/3
(Divide both sides by 3)
y=x+1
Step: Substitute x+1 for y in −3x+3y=−57:
−3x+3y=−57
−3x+3(x+1)=−57
3=−57 (Simplify both sides of the equation)
3+(−3)=−57+(−3) (Add -3 to both sides)
0=−60
2.4+3.06=5.46
5.46+.75=6.21
The answer is 6.21
The answer is: "
105 mi. " .
____________________________________________Explanation:____________________________________________Note that: "that amount of time" is "3 hours".
→ ![\frac{35 mi}{h} * \frac{3h}{1}](https://tex.z-dn.net/?f=%20%5Cfrac%7B35%20mi%7D%7Bh%7D%20%2A%20%5Cfrac%7B3h%7D%7B1%7D%20)
= ? ;
→ The units of "h" (for "hour/s") cancel out to "1" ; since ("h/h = 1") ;
→ and we are left with (35 * 3) mi.
= 105 mi. ____________________________________________ The answer is: "
105 mi. " .
____________________________________________