Answer:
30 m
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Explanation:
<u>We are given:</u>
Initial velocity (u) = 10 m/s
Final velocity (v) = 20 m/s
Time interval (t) = 2 seconds
Distance travelled by the bus (s) = s meters
<u>Solving for the distance travelled:</u>
<u>Solving for the acceleration:</u>
v = u + at [<em>first equation of motion</em>]
20 = 10 + a(2) [<em>replacing the given values</em>]
2a = 10 [<em>subtracting 10 from both sides</em>]
a = 5 m/s² [<em>dividing both sides by 2</em>]
<u>Solving for the distance:</u>
s = ut + 1/2 (at²) [<em>second equation of motion</em>]
s = 10(2) + 1/2(5)(2)² [<em>replacing the given values</em>]
s = 20 + 10
s = 30 m
Therefore, the bus travelled 30 m in the given time interval