during a 3.00 s time interval,the runners position changes from x1=50.0m to x2=30.5m what was the runners average velocity
1 answer:
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Let's call this "certain amount" with a variable, x, (since it's not specified in the question, I will assume that the answer shall just be based on this variable).
So every additional floor will make the building sink by x, and let's make the unit cm, so x cm.
Now we know that the maximum depression is 20 cm, and it is also
x*y, where y is the number of floors.
So we have x*y=20,
therefore the number of floors is:
20/x or
So every additional floor will make the building sink by x, and let's make the unit cm, so x cm.
Now we know that the maximum depression is 20 cm, and it is also
x*y, where y is the number of floors.
So we have x*y=20,
therefore the number of floors is:
20/x or
To solve this problem it is necessary to apply the concepts related to the Centrifugal Force and the Gravitational Force. Since there is balance on the body these two Forces will be equal, mathematically they can be expressed as
Where,
m = Mass
G =Gravitational Universal Constant
M = Mass of the Planet
r = Distance/Radius
Re-arrange to find the velocity we have,
At the same time we know that the period is equivalent in terms of the linear velocity to,
If our values are that the radius of mars is 3400 km and the distance above the planet is 100km more, i.e, 3500km we have,
Replacing we have,
Therefore the correct answer is C.