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Dovator [93]
3 years ago
10

during a 3.00 s time interval,the runners position changes from x1=50.0m to x2=30.5m what was the runners average velocity

Physics
1 answer:
UNO [17]3 years ago
7 0
Average velocity is given by the ratio of total displacement /total time taken in order to do that
thus it will be
30.5-50.0/3 = 6.5 m/s
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Let the rod be on the x-axes with endpoints -L/2 and L/2 and uniform charge density lambda (2.6nC/0.4m = 7.25 nC/m). 

The point then lies on the y-axes at d = 0.03 m. 

from symmetry, the field at that point will be ascending along the y-axes. 


A charge element at position x on the rod has distance sqrt(x^2 + d^2) to the point. 

Also, from the geometry, the component in the y-direction is d/sqrt(x^2+d^2) times the field strength. 


All in all, the infinitesimal field strength from the charge between x and x+dx is: 


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E = k lambda L / (d sqrt((L/2)^2 + d^2) ) 


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E = k Q / ( d * sqrt((L/2)^2 + d^2) )
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