Answer:
pH → 1.13
Explanation:
Our solution is pure HCl
HCl(aq) + H₂O(l) → H₃O⁺(aq) + Cl⁻(aq)
As a strong acid, it is completely dissociated.
1 mol of HCl, can give 1 mol of H⁺ to the medium. Water does not participate. Let's find out M for the acid.
1st step: We convert the mass from mg to g → 327 mg . 1g /1000mg = 0.327 g
2nd step: We convert the mass(g) to moles: 0.327 g / 36.45 g/mol = 8.97×10⁻³ moles
3rd step: We convert the volume from mL to L → 120mL . 1L /1000 mL = 0.120L
Molarity (mol/L) = 8.97×10⁻³ mol / 0.120L = 0.075M
We propose: HCl(aq) + H₂O(l) → H₃O⁺(aq) + Cl⁻(aq)
0.075M 0.075M
pH = - log [H₃O⁺] → - log 0.075 = 1.13 → pH
Answer:
Butan-2-ol
Explanation:
systematic name is also known as IUPAC name
if wrong , let me know I can edit the answer
Answer:
9.6 moles O2
Explanation:
I'll assume it is 345 grams, not gratis, of water. Hydrogen's molar mass is 1.01, not 101.
The molar mass of water is 18.0 grams/mole.
Therefore: (345g)/(18.0 g/mole) = 19.17 or 19.2 moles water (3 sig figs).
The balanced equation states that: 2H20 ⇒ 2H2 +02
It promises that we'll get 1 mole of oxygen for every 2 moles of H2O, a molar ratio of 1/2.
get (1 mole O2/2 moles H2O)*(19.2 moles H2O) or 9.6 moles O2
Magnesium combined with sulfuric acid produces magnesium sulfate and hydrogen gas.
First calculate the moles of CsOH.
moles CsOH = 0.217 M * 0.005 L = 0.001085 mol
We need 1 mole of HI per 1 mole of CsOH, therefore the
moles of HI needed is:
moles HI = 0.001085 mol
The volume required is therefore:
Volume = 0.001085 mol / 0.550 M
<span>Volume = 1.97x10^-3 L = 1.97 mL</span>