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NNADVOKAT [17]
3 years ago
12

Which type of a reaction is best represented by the equation - AB + CD → AD + BC?

Chemistry
1 answer:
Greeley [361]3 years ago
7 0

Answer

single displacement

Explanation:

It should be A, I think it is

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baherus [9]
By the lloks ofit you cant see it send a better picture
7 0
4 years ago
A proton is a subatomic particle carrying a charge equal to but opposite that of an electron
Pachacha [2.7K]

Answer:

True

Explanation:

A proton has a charge of +1, while an electron has a charge of -1. This is why a neutral atom has the same number of protons as electrons.

Neutrons have no charge, hence their name neutron which is similar to neutral.

8 0
3 years ago
Find the density of an 8 gram rock if the water in a graduated cylinder rises from 25.0 mL to
Olin [163]

To measure the density of the stone placed in a graduated cylinder let us follow these steps bellow

  1. Measure the volume of water poured into a graduated cylinder
  2. Place the object in the water and remeasure the volume.
  3. The difference between the two volume measurements is the volume of the object.
  4. Divide the mass by the volume to calculate the density of the object.

<em>We know that the formula for density is given as </em>

Given data

Mass = 8gram

Initial Volume of water in cylinder = 25mL

Final Volume of water in cylinder  = 29mL

Hence the volume of the rock  = 29-25 = 4mL

Therefore the density of the rock = 8/4 = 2 g/mL

Learn more:

brainly.com/question/17336041

6 0
3 years ago
ubstance A undergoes a first order reaction A®B with a half-life, t½, of 20 min at 25 °C. If the initial concentration of A in a
Stells [14]

Answer : The concentration of A after 80 min is, 0.100 M

Explanation :

Half-life = 20 min

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{20\text{ min}}

k=3.465\times 10^{-2}\text{ min}^{-1}

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 3.465\times 10^{-2}\text{ min}^{-1}

t = time passed by the sample  = 80 min

a = initial amount of the reactant  = 1.6 M

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

80=\frac{2.303}{3.465\times 10^{-2}}\log\frac{1.6}{a-x}

a-x=0.100M

Therefore, the concentration of A after 80 min is, 0.100 M

3 0
3 years ago
The Tyndall effect is used to distinguish between
docker41 [41]

A. solutions and colloids

3 0
4 years ago
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