Molar mass of oxygen gas:
O₂ = 16 * 2 = 32.0 g/mol
1 mole O₂ -------------- 32.0
9.05 mole O₂ ---------- ?
Mass = 9.05 * 32.0
Mass = 289.6 g of O₂
hope this helps!
I'm not sure, but I believe the correct answer is C.
The answer is
b)state of matter
because water is changing from a gas to liquid
The pressure of 1.27 L of a gas at 288°C, if the gas had a volume of 875 ml at 145 kPa and 176°C is 1.195 atm.
<h3>What is ideal gas equation?</h3>
Ideal gas equation of any gas will be represented as:
PV = nRT, where
P = pressure
V = volume
n = moles
R = universal gas constant
T = temperature
First we calculate the moles of gas, when the volume of gas 875 ml at
145 kPa and 176°C as:
n = (1.431atm)(0.875L) / (0.082L.atm/K.mol)(449.15K)
n = 1.252 / 36.83 = 0.033 moles
Now we measure the pressure of 0.033 moles of gas of 1.27 L of a gas at 288°C as:
P = (0.033mol)(0.082L.atm/K.mol)(561K) / (1.27L) = 1.195 atm
Hence required pressure of gas is 1.195 atm.
To know more about ideal gas equation, visit the below link:
brainly.com/question/555495
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