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3 years ago

I NEED HELP ASAP!!! THIS IS A 30 POINT QUESTION!!!

Chemistry

2 answers:

bekas [8.4K]3 years ago

6 0

Answer:

Explanation:

Protein synthesis involves two major steps:

<em>Transcription of the DNA to mRNA (a form of RNA)</em>
<em>Translation of the mRNA molecule into a protein.</em>

Transcription involves the formation of a nucleotide sequence complementary to the DNA molecule, with the pairing of a different base, Uracil, with Guanine instead of the usual Thymine base. This occurs in the nucleus of the cell, and the resulting molecule is known as the mRNA.

This mRNA is transported into the cytoplasm through the nuclear pore for the next step, translation. This is primarily accomplished by ribosomes and tRNA molecules which are present in the cytoplasm of the cell. The result of this step is the generation of a protein molecule.

<h3>Hope this helps</h3>

masya89 [10]3 years ago

5 0

Answer:

its A, C and E (1, 3, 5)

i did this on edgenuiti and it was correct =)

mark as brainliest i really need it bc if not i'll never level up i have 797/500 points

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Ghella [55]

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3 years ago

How many moles of carbon, hydrogen, and oxygen are present in a 100-g sample of ascorbic acid?

Y_Kistochka [10]

There are:

3.41 moles of C

4.54 moles of H

3.40 moles of O.

Why?

To solve the problem, the first thing that we need to do is to write the chemical formula of the ascorbic acid.

$C_{6}H_{8}O_{6}$

Now, we know that there are 100 grams of the compound, so, the masses of each element will represent the percent in the compound.

We have that:

$C_{6}=12.0107g*6=72.08g\\\\H_{8}=1.008g*8=8.064g\\\\O_{6}=15.999g*6=95.994g\\\\C_{6}H_{8}O_{6}=72.08g+8.064g+95.994g=176.138g$

To know the percent of each element, we need to to the following:

$C=\frac{72.08g}{176.138g}*100=0.409*100=40.92(percent)\\\\H=\frac{8.064g}{176.138g}*100=4.58(percent)\\\\O=\frac{95.994}{176.138g}*100=54.49(percent)$

So, we know that for the 100 grams of the compound, there are:

40.92 grams of C

4.58 grams of H

54.49 grams of O

We know the molecular masses of each element:

$C=12.0107\frac{g}{mol}\\\\H=1.008\frac{g}{mol}\\\\O=15.999\frac{g}{mol}{mol}$

Now, to calculate the number of moles of each element, we need to divide the mass of each element by the molecular mass of each element:

$C=\frac{40.92g}{12.010\frac{g}{mol}}=3.41mol\\\\H=\frac{4.58g}{1.008\frac{g}{mol}}=4.54mol\\\\O=\frac{54.49g}{15.999\frac{g}{mol}}=3.40mol$

Hence, we have that there are 3.41 moles of C, 4.54 moles of H, and 3.40 moles of O.

Have a nice day!

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3 years ago

Give the o.N. Of each of the elements magnesium and oxygen in the reactants and in the products 2Mg + O2=2MgO

vlada-n [284]

Answer:

$2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}$

Explanation:

Hello there!

In this case, according to the rules for the oxidation states in chemical reactions, it is possible to realize that lone elements have 0 and since magnesium is in group 2A, it forms the cation Mg⁺² as it loses electrons and oxygen is in group 6A so it forms the anion O⁻²; therefore resulting oxidation numbers are:

$2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}$

Best regards!

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miss Akunina [59]

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3 years ago

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