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BigorU [14]
2 years ago
8

Please answer this its really fast

Chemistry
1 answer:
Alex73 [517]2 years ago
4 0

Answer:

ugly

Explanation:

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Pure substance can be __ and __
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It can be an element or a compound
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What would happen if Earth was tilted at 45⁰ rather than 23.5⁰?
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Global warming

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3 years ago
A 13 Ohm resistor, R, is connected to a battery with unknown voltage, V, as shown below. The total current, I, flowing through t
wlad13 [49]

Answer:

16.12 V

Explanation:

Ohms law explains or portrays the relationship between the voltage (V), current (I) and resistance (R). This is represented using the equation as follows:

V = IR

Where;

V = voltage (Volts)

I = current (amperes)

R = resistance (ohms)

According to the information provided in the question, resistance (R) = 13 Ohm, current (I) = 1.24 Amperes, V = ?

V = 13 × 1.24

V = 16.12 V

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2 years ago
1. please :))))))))))))))))
natta225 [31]

Answer:

cierra los ojos que me vengo o me vengo

cierra los ojos que me vengo o me vengo

Explanation:

cierra los ojos que me vengo o me vengo cierra los ojos que me vengo o me vengo cierra los ojos que me vengo o me vengo cierra los ojos que me vengo o me vengo cierra los ojos que me vengo o me vengo cierra los ojos que me vengo o me vengo

8 0
2 years ago
A hot air balloon is filled with 1.31 × 10 6 L of an ideal gas on a cool morning ( 11 ∘ C ) . The air is heated to 121 ∘ C . Wha
victus00 [196]

Answer:

1.82\times 10^6 L is the volume of the air in the balloon after it is heated.

Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2} (at constant pressure)

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1= 1.31\times 10^6 L\\T_1=11^oC=(11+273.15)K=284.15K\\V_2=?\\T_2=121^oC=(121+273.15)K=394.15 K

Putting values in above equation, we get:

\frac{1.31\times 10^6 L}{284.15 K}=\frac{V_2}{394.14 K}\\\\V_2=\frac{V_1\times T_2}{T_1}

V_2=1.82\times 10^6 L

1.82\times 10^6 L is the volume of the air in the balloon after it is heated.

4 0
3 years ago
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