Moles of Carbon dioxide(CO2) = 2
<h3>Further explanation</h3>
Given
Reaction
2 C2H6 (g) + 7 O2 (g) —+ 4CO2 (g) + 6 H20 (g)
Required
moles of carbon dioxide
Solution
The reaction coefficient shows the mole ratio of the compounds in the reaction equation (reactants and products)
From the equation, mol ratio of C2H6 : CO2 = 2 : 4, so mol CO2 :
mol CO2 = (4/2) x mol C2H6
mol CO2 = 2 x 1
mol CO2 = 2
Moles of Na_2O
- Given mass/Molar mass
- 35/62
- 0.56mol
2 mols Na_2O produces 1 mol sodium carbonate.
1 mol sodium oxide produces 0.5mol sodium carbonate
Moles of sodium carbonate
Molar mass
- 2(23)+12+3(16)
- 46+12+48
- 106g/mol
Mass
Answer:
We take 20.0 mL of the 1.0 M fruit drink solution and then add 80.0 mL of water to make 100 mL of a 0.2 M fruit drink solution.
Explanation:
Using the rule that: the no. of millimoles of a solution before dilution is equal to the no. of millimoles of the solution after the dilution. (MV) before dilution = (MV) after dilution. M before dilution = 1.0 M, V before dilution = ??? mL. M after dilution = 0.2 M, V after dilution = 100 mL. ∴ V before dilution = (MV) after dilution / M before dilution = (0.2 M)(100 mL) / (1.0 M) = 20.0 mL. So, we take 20.0 mL of the 1.0 M fruit drink solution and then add 80.0 mL of water to make 100 mL of a 0.2 M fruit drink solution
