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3 years ago

Look at the data table and graph for the 25-coil electromagnet. With the 1.5 V battery, the

1 answer:

4 0

Answer a:
A 1.5 V battery, the electromagnet picked up an average of 6 paper clips, while with the 6.0 V battery, an average of 23 paper clips were picked up. Battery of 6.0V is 6.0/1.5 = 4 times stronger than battery of 1.5 V

Answer b:
Ratio of the number of paper clips picked up using the 6.0 V battery to the number picked up using the 1.5 V battery is = 23/6 = 3.8 ≈ 4.

Answer c:
As the voltage power increase, more paper clips were picked up by electromagnet. This indicated that there is a direct relationship. Mathematically it can be expressed as:

Voltage Power α Number of paper clips that were picked up

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Where does vanillin come from? PLEASE ANSWER

Mila [183]

Answer:

Vanillin, the main flavor component of cured vanilla beans, was synthesized variously from pine bark, clove oil, rice bran, and lignin

Explanation:

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3 years ago

What are the boiling points and freezing points (in oC) of a solution of 50.3 g of I2 in 350 g of chloroform? The kb = 3.63 oC/m

patriot [66]

Answer:

Boiling point: 63.3°C

Freezing point: -66.2°C.

Explanation:

The boiling point of a solution increases regard to boiling point of the pure solvent. In the same way, freezing point decreases regard to pure solvent. The equations are:

Boiling point increasing:

ΔT = kb*m*i

Freezing point depression:

ΔT = kf*m*i

ΔT are the °C that change boiling or freezing point.

m is molality of the solution (moles / kg)

And i is Van't Hoff factor (1 for I₂ in chloroform)

Molality of 50.3g of I₂ in 350g of chloroform is:

50.3g * (1mol / 253.8g) = 0.198 moles in 350g = 0.350kg:

0.198 moles / 0.350kg = 0.566m

Replacing:

Boiling point:

ΔT = kb*m*i

ΔT = 3.63°C/m*0.566m*1

ΔT = 2.1°C

As boiling point of pure substance is 61.2°C, boiling point of the solution is:

61.2°C + 2.1°C = 63.3°C

Freezing point:

ΔT = kf*m*i

ΔT = 4.70°C/m*0.566m*1

ΔT = 2.7°C

As freezing point is -63.5°C, the freezing point of the solution is:

-63.5°C - 2.7°C = -66.2°C

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3 years ago

How long will it take you to get to class 300 meters away if you go 0.5 m/s?

cricket20 [7]

Answer:

600 seconds, or 10 minutes

Explanation:

300m/ 0.5m = 600s

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2 years ago

Covalent bonds in a molecule absorb radiation in the IR region and vibrate at characteristic frequencies.

vazorg [7]

Answer:

$Frequency=1.6\times 10^{12}\ Hz$

Explanation:

The relation between frequency and wavelength is shown below as:

$c=frequency\times Wavelength
$

c is the speed of light having value $3\times 10^8\ m/s$

Given, Wavelength = 188 μm

Also, 1 μm = $10^{-6}$ nm

So,

Wavelength = $188\times 10^{-6}$ m

Thus, Frequency is:

$Frequency=\frac{c}{Wavelength}$

$Frequency=\frac{3\times 10^8}{188\times 10^{-6}}\ Hz$

$Frequency=1.6\times 10^{12}\ Hz$

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3 years ago

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