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svetlana [45]
3 years ago
7

Using Le Chatelier’s principle, predict which equilibrium system below decrease the concentration of the reactant (H2CO3) as a r

esult of the stress (change) added to the system.
The reaction being studied is: H2CO3(aq) H+(aq) + HCO3-(aq)

a. decrease H+ concentration by adding NaOH.
b. a catalyst is added.
c. Add more HCO3- by adding NaHCO3(s)
Chemistry
2 answers:
Diano4ka-milaya [45]3 years ago
8 0

Answer:

decrease H+ concentration by adding NaOH.

Explanation:

H2CO3→ H+ + HCO3-

A decrease in H^+ concentration will lead to a decrease of the H2CO3 concentration since more of it will now dissociate to the bicarbonate ion (equilibrium position shifts towards the right). This is because as equilibrium position shifts towards the right as the hydrogen ions are removed it decreases the concentration of the carbonic acid in the system as shown by the equation above.

seropon [69]3 years ago
4 0

Answer:

The correct answer is c add more HCO3- by adding NaHCO3.

Explanation:

The reaction mentioned in the question is carried out by bicarbonate buffer system of our body to maintain the normal acid  base balance.

         Now concentration of the reactant (H2C03) is decreased then NaHCO3 should be added which undergo breakdown to release bicarbonate ions(HCO3-).

        The released bicarbonate ions then reacts with H+ to form Carbonic acid(H2CO3).Thus homeostasis of H2CO3 is maintained.

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A gas with a volume of 4.0 L at a pressure of 2.02 atm is allowed to expand to a volume of 12.0
Maurinko [17]
<h3>Answer:</h3>

P₂ = 0.67 atm

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Chemistry</u>

<u>Gas Laws</u>

Boyle's Law: P₁V₁ = P₂V₂

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<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] P₁ = 2.02 atm

[Given] V₁ = 4.0 L

[Given] V₂ = 12.0 L

[Solve] P₂

<u>Step 2: Solve</u>

  1. Substitute in variables [Boyle's Law]:                                                              (2.02 atm)(4.0 L) = P₂(12.0 L)
  2. [Pressure] Multiply:                                                                                           8.08 atm · L = P₂(12.0 L)
  3. [Pressure] [Division Property of Equality] Isolate unknown:                          0.673333 atm = P₂
  4. [Pressure] Rewrite:                                                                                           P₂ = 0.673333 atm

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs as our smallest.</em>

0.673333 atm ≈ 0.67 atm

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