All compasses have a _____ inside that lines up with the earth’s magnetic north.

Elina [12.6K]

Answer:

(a) 106 kPa

(b) 0.0377 mol

(c) 17.8 cm

Explanation:

(a) There are three forces on the piston. Atmospheric pressure pushing down, weight pulling down, and pressure of the gas pushing up.

∑F = ma

PA − mg − PₐA = 0

P = (PₐA + mg) / A

P = Pₐ + (mg / A)

P = 101,300 Pa + (40.0 N) / (π (0.05 m²))

P = 106,393 Pa

P = 106 kPa

(b) Use ideal gas law.

PV = nRT

(106,393 Pa) (π (0.05 m²) (0.11 m)) = n (8.314 Pa m³/mol/K) (20 + 273.15) K

n = 0.0377 mol

(c) Use ideal gas law to find the new volume of the gas.

PV = nRT

(106,393 Pa) (π (0.05 m²) h) = (0.0377 mol) (8.314 Pa m³/mol/K) (200 + 273.15) K

h = 0.178 m

h = 17.8 cm

6 0

4 years ago

Read 2 more answers

A record of travel along a straight path is as follows:

nignag [31]

Answer:

a) Total displacement = 3986.54 m

b) Average speeds

Leg 1 -> 11.22 m/s

Leg 2 -> 22.44 m/s

Leg 3 -> 11.20 m/s

Complete trip -> 21.63 m/s

Explanation:

a) Leg 1:

Initial velocity, u = 0 m/s

Acceleration , a = 2.04 m/s²

Time, t = 11 s

We have equation of motion s= ut + 0.5 at²

Substituting

s= ut + 0.5 at²

s = 0 x 11 + 0.5 x 2.04 x 11²

s = 123.42 m

Leg 2:

We have equation of motion v = u + at

Initial velocity, u = 0 m/s

Acceleration , a = 2.04 m/s²

Time, t = 11 s

Substituting

v = 0 + 2.04 x 11 = 22.44 m/s

We have equation of motion s= ut + 0.5 at²

Initial velocity, u = 22.44 m/s

Acceleration , a = 0 m/s²

Time, t = 2.85 min = 171 s

Substituting

s= ut + 0.5 at²

s = 22.44 x 171 + 0.5 x 0 x 171²

s = 3837.24 m

a) Leg 3:

Initial velocity, u = 22.44 m/s

Acceleration , a = -9.73 m/s²

Time, t = 2.31 s

We have equation of motion s= ut + 0.5 at²

Substituting

s= ut + 0.5 at²

s = 22.44 x 2.31 + 0.5 x -9.73 x 2.31²

s = 25.88 m

Total displacement = 123.42 + 3837.24 + 25.88 = 3986.54 m

Average speed is the ratio of distance to time.

b) Leg 1:

$v_{avg}=\frac{123.42}{11}=11.22m/s$

Leg 2:

$v_{avg}=\frac{3837.24}{171}=22.44m/s$

Leg 3:

$v_{avg}=\frac{25.88}{2.31}=11.20m/s$

Complete trip:

$v_{avg}=\frac{3986.54}{11+171+2.31}=21.63m/s$

5 0

3 years ago

Arrange the values according to magnitude

Talja [164]

Answer:

$59000$

$1.8\times 10^5$

$4.3\times 10^{-2}$

$9.0\times 10^{-6}$

$8.4\times 10^{-6}$

Explanation:

The given numbers are

$1.8\times 10^5=18000$

$4.3\times 10^{-2}=0.043$

$8.4\times 10^{-6}=0.0000084
$

$9.0\times 10^{-6}=0.000009$

$59000$

The arrangement of the numbers from largest to smallest is

$59000$

$1.8\times 10^5$

$4.3\times 10^{-2}$

$9.0\times 10^{-6}$

$8.4\times 10^{-6}$ .

7 0

3 years ago

Which of the following best explains energy transformation in hydrogen fuel cells?Methane reacts with oxygen to produce carbon a

aivan3 [116]

Answer:

Hydrogen reacts with oxygen to produce water, which releases energy.

Explanation:

In any fuel cell chemical bonds are formed and energy is released . It is a redox reaction . Bond energy is converted into electrical energy.

In the given option , first option is not possible because methane reacts with oxygen to give carbon dioxide and water .

third and fourth option are ruled out because chemical reactions are using energy . No energy is released . so they are not possible.

3 0

3 years ago

What current is taken by the lamp when it is connected to a 220 v mains supply? what is the resistance of the lamp

eimsori [14]

Answer:

Given parameters

Potential difference (V) = 220 V

Power of lamp 1 (P1) = 100 W

Power of lamp 2 (P2) = 60 W

Both the bulbs are connected in parallel. Therefore, the potential difference across each of them will be 220 V, because no division of voltage occurs in a parallel circuit.

We know that

Power = Voltage x Current

P = V x I

I = P/V

Lamp 1:

I1 = P1/V

I1 = 100/220

I1 = 5/11 A

Lamp 2:

I2 = P2/V

I2 = 60/220

I2 = 3/11 A

Net current (I) = I1 + I2

I = 5/11 + 3/11

I = 8/11

I = 0.7273 A

Hence, current drawn from the line is 0.727 A

Explanation:

Hope this helps!

7 0

3 years ago