Explanation:
Mole ratio of Oxygen to Hydrogen gas = 1 : 2.
If we use 3.0 moles of oxygen gas, we would need 3.0 * 2 = 6.0 mol of hydrogen gas.
However we only have 4.2 mol of hydrogen. Therefore hydrogen is limiting and oxygen is in excess. (B)
Answer:
Common examples include hydrochloric acid, sulfuric acid, citric acid and ethanoic acid. Bases are a group of substances that neutralise acids. Soluble bases are called alkalis.
Explanation:
Hope this helps.
Hey there!:
Molar mass CuSO4*5H2O = 249.68 g/mol
Therefore:
1 mole CuSO4*5H2O ---------------- 249.68 g
3.2 moles --------------------------------- ?? ( mass of CuSO4*5H2O )
mass CuSO4*5H2O = 249.68 * 3.2
mass CuSO4*5H2O = 798.97 g
Hope that helps!
Thomson used a beam of negatively charged particles. Using a beam of particles and detecting the scattering of the particles after they hit gold foil.
