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Fynjy0 [20]
3 years ago
11

2. Petroleum is used to make

Chemistry
1 answer:
Nonamiya [84]3 years ago
5 0

Answer:

D. all of the above

Explanation:

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The exhaust gas from an automobile contains 1.5 percent by volume of carbon monoxide. What is the concentration of CO in mg/m' a
FrozenT [24]

Answer:

(a) 17,178 mg/m3

(b) 11,625 mg/m3

Explanation:

The concentration of CO in mg/m3 can be calculated as

C (mg/m3) =(P/RT)*MW*C_{ppm}

For standard conditions (1 atm and 25°C), P/RT is 0.0409.

Concentration of 1.5% percent by volume of CO is equivalent to 1.5*10,000 ppm= 15,000 ppm CO.

The molecular weigth of CO is 28 g/mol.

(1) For 25°C and 1 atm conditions

C=(P/RT)*MW*C_{ppm}\\\\C=0.0409*28*15,000=17,178

(b) For 200°C and 1.1 atm,

P/RT=0.0409*(P/P_{std})*(T_{std}/T)\\P/RT=0.0409*(1.1atm/1atm)*(273+15K/273+200K)=0.0277

Then the concentration in mg/m3 is

C=(P/RT)*MW*C_{ppm}\\\\C=0.0277*28*15,000=11,625

5 0
3 years ago
Which temperature is the hottest, 200°C, 200°F or 200 Kelvin?
gogolik [260]

Answer:

200 °C

Explanation:

Let’s convert all the temperatures to the same scale, say, Celsius.

<em>Celsius</em>

Water boils at 100 °C, so 200 °C is the temperature of <em>superheated steam</em>.

<em>Fahrenheit </em>

Water boils at 212 °F, so 200 °F is <em>just below the boiling point of water</em>.

C = \frac{5 }{ 9}(F-32)

C = \frac{5 }{ 9}(200-32) = \frac{5 }{ 9}\times168 = 93 ^{\circ}\text{C}

<em>Kelvin </em>

Standard temperature is 0 °C = 273.15 K. Ice melts at 273.15 K (0 °C), so

200 K is <em>well below the melting point of ice</em>.

C = K – 273.15

C = 200 -273.15 = -73 °C

Thus, 200 °C is the hottest temperature.

3 0
3 years ago
Why reactivity of elements in group 1 increase from lithium to francium?
labwork [276]

Answer:

As you go down group 1, the number of electron shells increases – lithium has two, sodium has three, and so forth. The attraction from the positive nucleus to the negative electron is less. This makes it easier to remove the electron and makes the atom more reactive.

3 0
3 years ago
Read 2 more answers
g How many grams of beryllium are needed to produce "11.5" g of hydrogen gas?Be(s) + 2H 2 O(l) → Be(OH) 2 (aq) + H 2 (g)
slega [8]

Answer:

m_{Be}=51.3gBe

Explanation:

Hello,

In this case, with the given chemical reaction:

Be(s) + 2H_2 O(l) \rightarrow Be(OH)_ 2 (aq) + H _2 (g)

We can notice a 1:1 mole ratio between hydrogen gas and beryllium metal, therefore, beryllium requirement is computed as shown below:

m_{Be}=11.5gH_2*\frac{1molH_2}{2.02gH_2} *\frac{1molBe}{1molH_2} *\frac{9.01gBe}{1molBe}\\ \\m_{Be}=51.3gBe

Regards.

6 0
3 years ago
Which of the following conditions most favors the process of dissolution?
Inga [223]
What following?? Conditions??
6 0
3 years ago
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