David hops in his 600-kg dune buggy and travels 20 m/s to the east. Meanwhile, Serap drives her 500-kg dune buggy at 30 m/s eas
1 answer:
1) David's momentum is 12,000 kg m/s east
2) Serap's momentum is 15,000 kg m/s east
3) The total momentum is 27,000 kg m/s east
Explanation:
1)
The momentum of an object is given by
where
m is the mass of the object
v is its velocity
In this problem, we have:
m = 600 kg is the mass of David+his dune buggy
is their velocity (taking east as positive direction)
Therefore, David's momentum is:
And the direction is the same as the velocity (east).
2)
Again, we can use the same equation:
where this time
m is the mass of Serap+dunebuggy
v is their velocity
In this problem,
m = 500 kg is the mass of Serap + dunebuggy
v = 30 m/s is their velocity (positive since it is also in the east direction)
Substituting, we find
And the direction is the same as the velocity (east).
3)
The total momentum of the entire system is given by
where
is David's momentum
is Serap's momentum
In this problem, we have the following data, found in the previous parts:
The two momentum have same direction (east), so we can simply add them together to find the total momentum:
And the direction is still East.
Learn more about momentum:
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Answer:
6.96 s
Explanation:
<u>Given:</u>
- u = initial speed of the automobile = 0 m/s
- a = constant acceleration of the automobile =
- v = constant speed of the truck = 8.7 m/s
<u>Assume:</u>
- t = time instant at which the automobile overtakes the truck.
At the moment the automobile and the truck both meat each other the distance travel by both vehicles must be the same.
Since t = 0 s is the initial condition. So, they both meet again at t = 6.96 s such that the automobile overtakes the truck.
The elastic potential energy of a spring is given by
where k is the spring's constant and x is the displacement with respect to the relaxed position of the spring.
The work done by the spring is the negative of the potential energy difference between the final and initial condition of the spring:
In our problem, initially the spring is uncompressed, so
. Therefore, the work done by the spring when it is compressed until 
is
And this value is actually negative, because the box is responsible for the spring's compression, so the work is done by the box.
where k is the spring's constant and x is the displacement with respect to the relaxed position of the spring.
The work done by the spring is the negative of the potential energy difference between the final and initial condition of the spring:
In our problem, initially the spring is uncompressed, so
And this value is actually negative, because the box is responsible for the spring's compression, so the work is done by the box.