Question

David hops in his 600-kg dune buggy and travels 20 m/s to the east.  Meanwhile, Serap drives her 500-kg dune buggy at 30 m/s east and tries to catch David.
What is davids momentum?

what is serap's momentum

what is the total momentum of the entire system?
​

Answer 1

1) David's momentum is 12,000 kg m/s east

2) Serap's momentum is 15,000 kg m/s east

3) The total momentum is 27,000 kg m/s east

Explanation:

1)

The momentum of an object is given by

$p=mv$

where

m is the mass of the object

v is its velocity

In this problem, we have:

m = 600 kg is the mass of David+his dune buggy

$v=20 m/s$ is their velocity (taking east as positive direction)

Therefore, David's momentum is:

$p_d = (600)(20)=12,000 kg m/s$

And the direction is the same as the velocity (east).

2)

Again, we can use the same equation:

$p=mv$

where this time

m is the mass of Serap+dunebuggy

v is their velocity

In this problem,

m = 500 kg is the mass of Serap + dunebuggy

v = 30 m/s is their velocity (positive since it is also in the east direction)

Substituting, we find

$p_s = (500)(30)=15,000 kg m/s$

And the direction is the same as the velocity (east).

3)

The total momentum of the entire system is given by

$p = p_d + p_s$

where

$p_d$ is David's momentum

$p_s$ is Serap's momentum

In this problem, we have the following data, found in the previous parts:

$p_d = 12,000 kg m/s$

$p_s = 15,000 kg m/s$

The two momentum have same direction (east), so we can simply add them together to find the total momentum:

$p=12,000 + 15,000 = 27,000 kg m/s$

And the direction is still East.

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