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FromTheMoon [43]
3 years ago
11

The diagram represents liquid water in a pan on a hot plate. The liquid water is boiling and changing into water vapor. The proc

ess of boiling water is considered to be a

Chemistry
2 answers:
Ierofanga [76]3 years ago
6 0

Answer:

I guess c?

Explanation:

take my answer by a grain of salt but the process of boiling water leads to physical change because eventually all water will become water vapor if boiled long enough

pogonyaev3 years ago
3 0
C is the answer to this question hope it’s right
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Is Pb(NO3)2 soluble or insoluble?
Sedaia [141]

Answer: it is soluble

Explanation: nitrates are soluble.

4 0
3 years ago
A student asked to convert measurements from liters to mililiters and from mililiters to liters. His answers are shown in bold i
LenaWriter [7]

Answer:   3.6 L = 3600

Explanation: 3.6 L = 360 mL has a mistake. He multiplied by 100 instead of 1000.

5 0
4 years ago
What are the missing coefficients for the skeleton equation below?
Vika [28.1K]

Answer:

C. Double Replacement

Explanation:

A. Wrong because SR uses a compound and element. This equation is a compound and compound.

B. Wrong because it does not have O2 in the formula. All combustion reactions must have O2.

C. Correct because it is a compound reacting with a compound.

D. Wrong because the reactants did not form a single product. ex. (x + y > xy)

E. Wrong because the equation did not start with a single compound and break down. ex. (xy > x + y)

3 0
3 years ago
Stu Dent has finished his titration, and he comes to you for help with the calculations. He tells you that 20.00 mL of unknown c
Alexus [3.1K]

Answer:

0.3229 M HBr(aq)

0.08436M H₂SO₄(aq)

Explanation:

<em>Stu Dent has finished his titration, and he comes to you for help with the calculations. He tells you that 20.00 mL of unknown concentration HBr(aq) required 18.45 mL of 0.3500 M NaOH(aq) to neutralize it, to the point where thymol blue indicator changed from pale yellow to very pale blue. Calculate the concentration (molarity) of Stu's HBr(aq) sample.</em>

<em />

Let's consider the balanced equation for the reaction between HBr(aq) and NaOH(aq).

NaOH(aq) + HBr(aq) ⇄ NaBr(aq) + H₂O(l)

When the neutralization is complete, all the HBr present reacts with NaOH in a 1:1 molar ratio.

18.45 \times 10^{-3} L NaOH.\frac{0.3500molNaOH}{1LNaOH} .\frac{1molHBr}{1molNaOH} .\frac{1}{20.00 \times 10^{-3} LHBr} =\frac{0.3229molHBr}{1LHBr} =0.3229M

<em>Kemmi Major also does a titration. She measures 25.00 mL of unknown concentration H₂SO₄(aq) and titrates it with 0.1000 M NaOH(aq). When she has added 42.18 mL of the base, her phenolphthalein indicator turns light pink. What is the concentration (molarity) of Kemmi's H₂SO₄(aq) sample?</em>

<em />

Let's consider the balanced equation for the reaction between H₂SO₄(aq) and NaOH(aq).

2 NaOH(aq) + H₂SO₄(aq) ⇄ Na₂SO₄(aq) + 2 H₂O(l)

When the neutralization is complete, all the H₂SO₄ present reacts with NaOH in a 1:2 molar ratio.

42.18 \times 10^{-3} LNaOH.\frac{0.1000molNaOH}{1LNaOH} .\frac{1molH_{2}SO_{4}}{2molNaOH} .\frac{1}{25.00\times 10^{-3}LH_{2}SO_{4}} =\frac{0.08436molH_{2}SO_{4}}{1LH_{2}SO_{4}} =0.08436M

6 0
3 years ago
How many atoms of mercury are present in 3.2 cubic centimeters of liquid mercury? the density of mercury is 13.55 g/cc. answer i
jenyasd209 [6]

Answer:

             1.3 × 10²³ Atoms of Mercury  

Solution:

Step 1: Calculate Mass of Mercury using following formula,

                               Density  =  Mass ÷ Volume

Solving for Mass,

                               Mass  =  Density × Volume

Putting values,

                               Mass  =  13.55 g.cm⁻³ × 3.2 cm³                ∴ 1 cm³ = 1 cc

                               Mass  =  43.36 g

Step 2: Calculating number of Moles using following formula;

                               Moles  =  Mass ÷ M.mass

Putting values,

                               Moles  =  43.36 g ÷ 200.59 g.mol⁻¹

                               Moles  =  0.216 mol

Step 3: Calculating Number of Atoms using following formula;

                               Number of atoms  =  Moles × 6.022 ×10²³

Putting value of moles,

                               Number of Atoms  =  0.216 mol × 6.022 × 10²³

                              Number of Atoms  =  1.3 × 10²³ Atoms of Hg

7 0
3 years ago
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