An increase in the surface area of reactants in a heterogeneous reaction will result in what?

A permeation membrane separates an inlet air stream, F, (79 mol% N2, 21 mol% O2), into a permeate stream, M, and a reject stream

Norma-Jean [14]

Answer:

Permeate stream: M=10,47 L/min
Reject stream: J=38,24 L/min

Explanation:

Using the law of mass conservation, we have that the moles of any component in the inlet air stream equals the moles of this compenent in the two outlets stream. Being A the mole flowrate for the permeate stream and B the mole flowrate for the reject stream (both in mol/min), we have equation (1) and (2):

Oxygen:

2 mol/min * 0,21 = A mol/min * 0,50 + B mol/min * 0,13 ......................(1)

0,42 = 0,5A + 0,13B...........................(1)

Nitrogen:

2 mol/min * 0,79 = A mol/min * 0,50 + B mol/min * 0,87 ......................(2)

1,58 = 0,5A + 0,87B...........................(2)

Solving this system:

1,58 = 0,5A + 0,87B...........................(2)

0,42 = 0,5A + 0,13B...........................(1)

1,16 = 0A + 0,74B...............................(2) - (1)

1.16=0,74B

1,16/0,74=B

B=1,57 mol/min

And now replacing B in equation (1):

1,58 = 0,5A + 0,87*1,57

1,58-1,37=0,5A

0,21/0,5=A

A=0,43 mol/min

To calculate the volumetric flowrate of the permeate stream (M) and the reject stream (J), we just replace the given and calculate data into the ideal gas equation:

PV=nRT,.................... V = nRT/P

Permeate stream:

$M= \frac{0,43 \frac{mol}{min}*8,314\frac{m3Pa}{molK}*293K }{0,1 MPa*\frac{10^{6}Pa }{1 MPa} }=0,01047\frac{m^{3} }{min} * \frac{1000 L}{1 m^{3} }=10,47 L/min$

Rejct stream:

$J= \frac{1,57 \frac{mol}{min}*8,314\frac{m3Pa}{molK}*293K }{0,1 MPa*\frac{10^{6}Pa }{1 MPa} }=0,0382\frac{m^{3} }{min} * \frac{1000 L}{1 m^{3} }=38,24 L/min$

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Table salt is insoluble in water. true or false

Zielflug [23.3K]

Answer:

False. It is soluble in water.

Explanation:

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ivanzaharov [21]

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No, that sort of reaction do not form named compounds.

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Technology used during a scientific experiment to gather data

ddd [48]

Hi!

The answer to this is true.

Hope it helps! :)

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Differentiate between the three types of simple permanent tissues on the basis of their cell walls

True [87]

Answer:

Parenchyma is the most simple and specialized tissue which is concerned mainly with the vegetative activities of the plant. The cells are isodiametric with well-developed intercellular spaces, vacuolated cytoplasm and cellulosic cell wall.

Collenchyma is the tissue of the primary body. The cells of the tissue contain protoplasm and are living without intercellular spaces. The cell wall articulate at the corners and are made up of cellulose, hemicellulose, and pectin.

Sclerenchyma is the thick-walled cell tissue. In the beginning, the cell is living and have protoplasm, but due to deposition of impermeable secondary board lignin, they become dead thick and hard.

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