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givi [52]
3 years ago
8

You have a stock solution of HNO3 with a concentration of 4.5 x 10^-4 M. However, you need 275 ml of a 2.50 x 10^-5 M solution.

How much of the stock solution will you need?
Chemistry
1 answer:
Reptile [31]3 years ago
4 0

Answer:

15.28 mL

Explanation:

From the question given above, the following data were obtained:

Molarity of stock solution (M₁) = 4.5x10¯⁴ M

Volume of diluted solution (V₂) = 275 mL

Molarity of diluted solution (M₂) = 2.5×10¯⁵ M

Volume of stock solution (V₁) needed =.?

The volume of the stock solution needed can be obtained by using the dilution formula as illustrated below:

M₁V₁ = M₂V₂

4.5x10¯⁴ × V₁ = 2.5×10¯⁵ × 275

4.5x10¯⁴ × V₁ = 0.006875

Divide both side by 4.5x10¯⁴

V₁ = 0.006875 / 4.5x10¯⁴

V₁ = 15.28 mL

Therefore, the volume of the stock solution needed is 15.28 mL

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Fill in the coefficients that will balance the following reaction:
Vesnalui [34]
These are 9 questions and 9 aswers.

1) Fill in the coefficients that will balance the following reaction:<span>

A₀ Hg(CO₃)₂ + A₁ AgCl → A₂HgCl₄ + A₃Ag₂CO₃

Answer:

Balance in Hg ⇒ A₀ = A2
Balance in Ag ⇒ A₁ = 2A₃
Balance is CO₃ ⇒ 2A₀ = A₃
Balance is Cl ⇒A₁ = 4Cl₄

⇒ System of equations:

</span><span><span>A₀ = A2
A₁ = 2A₃
2A₀ = A₃
A₁ = 4A₂</span>

Start by stating A₂ = 1

⇒ A₁ = 4
    A₃ = 4/2 = 2
    A₀ = 2/2 = 1

Therefore, the resulting balanced reaction is:

</span><span>Hg(CO₃)₂ + 4 AgCl → HgCl₄ + 2 Ag₂CO₃ <-------- answer

2) Fill in the coefficients that will balance the following reaction:

a₀ Fe(HCO₃)₃ + a₁CaO → a₂Fe₂O₃ + a₃Ca(HCO₃)₂

Answer:

Balance in Fe: a₀ = 2a₂
Balance in H: 3a₀ = 2a₃
Balance in C: 3a₀ = 2a₃
Balance in O: 9a₀ = 3a₂ + 6a₃
Balance in Ca: a₁ = a₃

Start with a₃ = 3

⇒ a₀ = 2
    a₁ = 3
    a₂ = 1
    a₃ = 3

Therefore, the resulting balanced equation is:

</span><span>2 Fe(HCO₃)₃ + 3CaO → Fe₂O₃ + 3 Ca(HCO₃)₂   <----------- answer

3) Fill in the coefficients that will balance the following reaction:

a₀C₃H₇OH + a₁O₂ → a₂CO₂ + a₃H₂O

Answer:

Balance in C: 3a₀ = a₂
Balance in H: 8a₀ = 2a₃
Balance in O: a₀ + 2a₁ = 2a₂ + a₃

Start with a₃ = 4 ⇒

a₀ = 1
a₂ = 3
1 + 2 a₁ = 2×3 + 4 ⇒ a₁ = 4,5

to make alll the coefficients integers multiply by 2:

a₃ = 8
a₀ = 2
a₂ = 6
a₁ = 9

Therefore, the resulting balanced chemical equation is:
</span>
<span> 2C₃H₇OH + 9O₂ → 6CO₂ + 8H₂O

4) Fill in the coefficients that will balance the following reaction:

a₀SnSO₄ + a₁KBr → a₂SnBr₂ + a₃K₂SO₄

Answer:

Balance in Sn: a₀ = a₂
Balance in SO₄: a₀ = a₃
Balance in K: a₁ = 2a₃
Balance in Br: a₁ = 2a₂

Start with a₃ = 1 ⇒

a₀ = 1
a₁ = 2
a₂ = 1

Therefore, the resulting balance equation is:
</span>
<span> SnSO₄ + 2KBr → SnBr₂ + K₂SO₄  <------------ answer

5) Fill in the coefficients that will balance the following reaction:

a₀NH4Cl + a₁Ag3PO4 → a₂AgCl + a₃(NH4)3PO4

a₂ = 3
a₁ = 1
a₀ = 3
a₃ = 1

⇒ </span><span>3 NH₄Cl + Ag₃PO₄ → 3 AgCl + (NH₄)₃PO₄ <-------- answer

6) Fill in the coefficients that will balance the following reaction:

a₀Cr₂(SO₄)₃ + a₁AgNO₃ → a₂Cr(NO₃)₃ + a₃Ag₂SO₄

Answer:

a₀ = 1
a₁ = 6
a₂ = 2
a₃ = 3

Resulting balanced equation:

</span><span>Cr₂(SO₄)₃ + 6AgNO₃ → 2Cr(NO₃)₃ + 3Ag₂SO₄

7) Fill in the coefficients that will balance the following reaction:

a₀NaC₂H₃O₂ + a₁Fe₂O₃ → a₂Fe(C₂H₃O₂)₃ + a₃Na₂O

Answer:

Balance in Na: a₀ = 2a₃
Balance in </span><span>C₂H₃O₂ : a₀ = 3a₂
Balance in Fe: 2a₁ = a₂
Balance in O: 3a₁ = a₃

Start with a₃ = 3 ⇒

a₁ = 1
a₂ = 2
a₀ = 6

⇒ </span><span>6NaC₂H₃O₂ + Fe₂O₃ → 2Fe(C₂H₃O₂)₃ + 3Na₂O ← answer

8) Fill in the coefficients that will balance the following reaction:
a₀CH₄ + a₁O₂ → a₂CO₂ + a₃H₂O

a₀ = 1
a₁ = 2
a₂ = 1
a₃ = 2

⇒ </span><span>CH₄ + 2O₂ → CO₂ + 2H₂O ← answer

9) Fill in the coefficients that will balance the following reaction:
a₀NaCl + a₁FeO → a₂Na₂O + a₃FeCl₂

Answer:

a₀ = 2
a₁ = 1
a₂ = 1
a₃ = 1

</span>2NaCl + FeO → Na₂O + FeCl₂ ← answer











5 0
3 years ago
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