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givi [52]
3 years ago
8

You have a stock solution of HNO3 with a concentration of 4.5 x 10^-4 M. However, you need 275 ml of a 2.50 x 10^-5 M solution.

How much of the stock solution will you need?
Chemistry
1 answer:
Reptile [31]3 years ago
4 0

Answer:

15.28 mL

Explanation:

From the question given above, the following data were obtained:

Molarity of stock solution (M₁) = 4.5x10¯⁴ M

Volume of diluted solution (V₂) = 275 mL

Molarity of diluted solution (M₂) = 2.5×10¯⁵ M

Volume of stock solution (V₁) needed =.?

The volume of the stock solution needed can be obtained by using the dilution formula as illustrated below:

M₁V₁ = M₂V₂

4.5x10¯⁴ × V₁ = 2.5×10¯⁵ × 275

4.5x10¯⁴ × V₁ = 0.006875

Divide both side by 4.5x10¯⁴

V₁ = 0.006875 / 4.5x10¯⁴

V₁ = 15.28 mL

Therefore, the volume of the stock solution needed is 15.28 mL

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dlinn [17]

Answer:

The coefficients are 2 for H₂O and 1 for Ca(OH)₂.

Explanation:

Let's consider the following reaction.

Ca(OH)₂(aq) + 2 HCl(aq) → CaCl₂(aq) + 2 H₂O(l)

According to the balanced equation, the molar ratio of H₂O to Ca(OH)₂ is 2:1. Using this conversion factor, we have the following proportion:

moles Ca(OH)₂. (2 mol H₂O ÷ 1 mol Ca(OH)₂) = moles H₂O

4 0
3 years ago
How many grams of lead(II) sulfate (303 g/mol) are needed to react with sodium chromate (162 g/mol) in order to produce 0.162 kg
Afina-wow [57]

Answer : The mass of PbSO_4 needed are, 1.515 grams.

Explanation :

First we have to calculate the mole of PbCrO_4.

\text{Moles of }PbCrO_4=\frac{\text{Mass of }PbCrO_4}{\text{Molar mass of }PbCrO_4}=\frac{0.162g}{323g/mole}=0.005mole

Now we have to calculate the moles of PbSO_4.

The balanced chemical reaction will be,

PbSO_4+Na_2CrO_4\rightarrow PbCrO_4+Na_2SO_4[tex]From the balanced chemical reaction, we conclude thatAs, 1 mole of [tex]PbCrO_4 produced from 1 mole of PbSO_4

So, 0.005 mole of PbCrO_4 produced from 0.005 mole of PbSO_4

Now we have to calculate the mass of PbSO_4

\text{Mass of }PbSO_4=\text{Moles of }PbSO_4\times \text{Molar mass of }PbSO_4

\text{Mass of }PbSO_4=0.005mole\times 303g/mole=1.515g

Therefore, the mass of PbSO_4 needed are, 1.515 grams.

6 0
3 years ago
In today's pandemic,how can you protect our ozone depletion?​
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Answer:

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5 0
3 years ago
How do i find a ionic formula? <br><br>for example Ca2+ &amp; S2-​
jeka94

Example #1 write the chemical formula for Calcium Oxide

Step 1

-Find the Atomic symbol of the metal and non-metal on the periodic table

CaO

Step 2

Find the charges for Calcium and Oxygen

which are Ca 2+ and O 2-

Step 3

Balance out the charges

They are already balanced out

Here´s the chemical formula for Calcium Oxide

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Example 2 write the chemical formula for Aluminum Oxide

Step 1

-Find the Atomic symbol of the metal and non-metal on the periodic table

A

l

O

Step 2

Find the charges for Aluminum and Oxygen

Which are Al 3+ and O 2-

Step 3

Balance out the charges

You need 2 Aluminum and 3 Oxygen to balance the charges

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= 6 + O 2-

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Step 4

If you need more then one element to balance out the charges you identify that by using subscripts

Heres your chemical formula for Aluminum Oxide

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8 0
3 years ago
When a piston is pushed down on a cylinder, the pressure on the gas in the cylinder increases from 125 kPa to 375 kPa. The initi
Elden [556K]

Answer:

The final volume is 1.1 L.

Explanation:

Given data:

Initial pressure of gas = 125 KPa

Final pressure of gas = 375 KPa

Initial volume = 3.3 L

Final volume = ?

Solution:

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

125 Kpa × 3.3 L = 375 Kpa × V₂

V₂ = 412.5 KPa. L/375 Kpa

V₂ = 1.1 L

The volume of gas is reduced to the 1.1 L because of increasing pressure.

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