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Aleks [24]
3 years ago
12

Consider the following intermediate chemical equations.

Chemistry
1 answer:
Degger [83]3 years ago
4 0

Answer:

-1,300 kJ

I don't want to explain it brainly AAAAA

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Which statement about melting and boiling points is true? Question 3 options:
bonufazy [111]

Answer:

B

Explanation:

I believe it is B but I am not entirely sure! don't do this is B doesn't sound or look right to you!

4 0
3 years ago
____CO + ____H2 ----> ____C8H18 +____H2O
masha68 [24]
8CO+9H2 —> 1 C8H18+9H2O
3 0
3 years ago
2.
Alex777 [14]

Answer:

C. 500 cm' of 1.0 mol dmº magnesium sulphate solution.

Explanation:

Let us look at each of the solutions individually;

CaCl2  has three particles

K2SO4 has three particles

MgSO4 has two particles

C2H5OH has only one particle

The number of moles of moles in 250 cm of 2.0 mol dm-3 potassium chloride is 250/1000 * 2 = 0.5 moles having two particles

Also; number of moles in 500 cm' of 1.0 mol dm-3 magnesium sulphate solution= 500/1000 * 1 = 0.5 moles having two particles

5 0
3 years ago
Henry divides 1.060 g by 1.0 mL to find the density of his water sample. How many significant figures should he include in the
goldfiish [28.3K]

Answer:

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Given data:

Mass = 1.060 g

Volume = 1.0 mL

Density in correct number of significant figures=  ?

Solution:

d = m/v

d = 1.060 g /  1.0 mL

d = 1.06 g/ mL

The density 1.06 g/mL contain three significant figures Henry should report it 1.1 g/mL having the only one digit after decimal because in given values 1.060 and 1.0 the least number of significant figures after the decimal is 1 that's why the final result must have one significant figure after  decimal.

8 0
3 years ago
How many moles are present in 88.0 g of KCN?
Kruka [31]
I think so x=1,35 moles
7 0
3 years ago
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