Consider the following intermediate chemical equations.
1 answer:
You might be interested in
Answer:
Reagents: 1) 2)
,
Mechanism: Hydroboration
Explanation:
In this case, we have a <u>hydration of alkene</u>s reaction. But, in this example, we have an <u>anti-Markovnikov reaction</u>. In other words, the "OH" is added in the least substituted carbon. Therefore we have to choose an anti-Markovnikov reaction: <u>"hydroboration"</u>.
The <u>first step</u> of this reaction is the addition of borane () to the double bond. Then in the <u>second step</u>, we have the deprotonation of the hydrogen peroxide, to obtain the peroxide anion. In the <u>third step</u>, the peroxide anion attacks the molecule produced in the first step to produce a complex compound in which we have a bond "
". In <u>step number 4</u> we have the migration of the C-B bond to oxygen. Then in <u>step number 5</u>, we have the attack of
on the
to produce an alkoxide. Finally, the water molecule produce in step 2 will <u>protonate</u> the molecule to produce the alcohol.
See figure 1
I hope it helps!
The frequency of light having a wavelength of 425nm will be 70588 × .
The count of times an event takes place per unit of time is known as its frequency. The word frequency would be most frequently used to describe waves in physics including chemistry, including light, sound, including radio waves. The frequency refers to the number of times during one second that a point on a wave crosses a fixed reference point.
A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places in the consecutive cycles.
Given data:
wavelength = 425nm =
Frequency can be calculated by using the formula;
Frequency = speed of light / wavelength
Frequency = 3 × / 425 ×
= 7,0588 ×
.
Therefore, the frequency of light having a wavelength of 425nm will be 70588 × .
To know more about frequency
#SPJ4