We have thatThe options that define Speed, Velocity,Acceleration.
- Speed is used to describe how fast the object is moving.
- Acceleration is the rate of change of velocity in time.
- Velocity is used to describe how fast the object is moving and tells us in which direction it is going.
Options
B,D,E
From the question we are told
Choose the correct definitions of speed, velocity, and acceleration. Check all that apply.
- Acceleration tells us in which direction the object is going. Speed is the rate of change of velocity in time.
- Acceleration is the rate of change of velocity in time.
- Velocity is used to describe changes in the movement direction of the object. Acceleration tells us how far the object will go in a certain amount of time.
- Velocity is used to describe how fast the object is moving and tells us in which direction it is going.
- Speed is used to describe how fast the object is moving.
- Velocity is the rate of change of speed in time.
Speed is used to describe how fast the object is moving and tells us in which direction it is going.
Generally
- Acceleration is the rate of change of velocity in time.
- Velocity is used to describe how fast the object is moving and tells us in which direction it is going.
- Speed is used to describe how fast the object is moving without its direction in consideration
Hence
The options that define Speed, Velocity,Acceleration.
- Speed is used to describe how fast the object is moving.
- Acceleration is the rate of change of velocity in time.
- Velocity is used to describe how fast the object is moving and tells us in which direction it is going.
Options
B,D,E
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Answer:
Hz
Explanation:
We know that
1 cm = 0.01 m
= Length of the human ear canal = 2.5 cm = 0.025 m
= Speed of sound = 340 ms⁻¹
= First resonant frequency
The human ear canal behaves as a closed pipe and for a closed pipe, nth resonant frequency is given as
for first resonant frequency, we have n = 1
Inserting the values
Hz
Explanation:
Fgravity = G*(mass1*mass2)/D².
G is the gravitational constant, which has the same value throughout our universe.
D is the distance between the objects.
so, if you triple one of the masses, what does that do to our equation ?
Fgravitynew = G*(3*mass1*mass2)/D²
due to the commutative property of multiplication
Fgravitynew = 3* G*(mass1*mass2)/D² = 3* Fgravity
so, the right answer is 3×12 = 36 units.
<h2>Answer:</h2><h2> b hopefully this helps you with work </h2>
