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3 years ago

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In the triangle XYZ the measure of angle YXZ is 50 degrees and the measure of angle XYZ is 75 degrees. What is the measure of an

gle XZY?

2 answers:

lbvjy [14]3 years ago

8 0

<h2>Answer: 55 degrees</h2>

Step-by-step explanation:

Every triangle has 3 sides and 3 interior angles whose measures sum to 180 degrees. For example, a triangle with angles $\theta$ , $\alpha$ and $\beta$ :

$\theta+\alpha+\beta=180\º$

Following this rule, we will apply it to the angles XYZ, YXZ and the unknown XZY:

$XYZ+YXZ+XZY=180\º$

$50\º+75\º+XZY=180\º$

$XZY=180\º-50\º-75\º$

Finally:

$XZY=55\º$

Strike441 [17]3 years ago

4 0

Answer:

it is c 2.5

Step-by-step explanation:

i just did it

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4 years ago

A school wishes to enclose its rectangular playground using 480 meters of fencing.

Harlamova29_29 [7]

Answer:

Part a) $A(x)=(-x^2+240x)\ m^2$

Part b) The side length x that give the maximum area is 120 meters

Part c) The maximum area is 14,400 square meters

Step-by-step explanation:

The picture of the question in the attached figure

Part a) Find a function that gives the area A(x) of the playground (in square meters) in terms of x

we know that

The perimeter of the rectangular playground is given by

$P=2(L+W)$

we have

$P=480\ m\\L=x\ m$

substitute

$480=2(x+W)$

solve for W

$240=x+W\\W=(240-x)\ m$

<u><em>Find the area of the rectangular playground</em></u>

The area is given by

$A=LW$

we have

$L=x\ m\\W=(240-x)\ m$

substitute

$A=x(240-x)\\A=-x^2+240x$

Convert to function notation

$A(x)=(-x^2+240x)\ m^2$

Part b) What side length x gives the maximum area that the playground can have?

we have

$A(x)=-x^2+240x$

This function represent a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

The x-coordinate of the vertex represent the length that give the maximum area that the playground can have

Convert the quadratic equation into vertex form

$A(x)=-x^2+240x$

Factor -1

$A(x)=-(x^2-240x)$

Complete the square

$A(x)=-(x^2-240x+120^2)+120^2$

$A(x)=-(x^2-240x+14,400)+14,400$

$A(x)=-(x-120)^2+14,400$

The vertex is the point (120,14,400)

therefore

The side length x that give the maximum area is 120 meters

Part c) What is the maximum area that the playground can have?

we know that

The y-coordinate of the vertex represent the maximum area

The vertex is the point (120,14,400) -----> see part b)

therefore

The maximum area is 14,400 square meters

Verify

$x=120\ m$

$W=(240-120)=120\ m$

The playground is a square

$A=120^2=14,400\ m^2$

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