Answer:
T2= 7.3°C
Explanation:
To solve this problem we will use Charles law equation i.e,
V1/T1 = V2/T2
Given data
V1 = 269.7 L
T1 = 6.12 °C
V2= 320.4 L
T2=?
Solution:
Now we will put the values in equation
269.7 L / 6.12°C = 320.4 L / T2
T2= 320.4 L × 6.12°C/ 269.7 L
T2= 1960.85 °C. L /269.7 L
T2= 7.3°C
Answer:
the volume of a set of keys is 6.75ml
Answer:
Lithium oxide, Li₂O.
Explanation:
Hello!
In this case, according to the given amounts, it is possible to write down the chemical reaction as shown below:
Which means that the metallic oxide has the following formula: M₂O. Next, we can set up the following proportional factors according to the chemical reaction:
Thus, we perform the operations in order to obtain:
So we solve for x as shown below:
Whose molar mass corresponds to lithium, and therefore, the metallic oxide is lithium oxide, Li₂O.
Best regards!
Answer:
976.8 g
Explanation:
C₅H₁₂ + 8O₂ → 5CO₂ + 6H₂0 ------------(1)
number of moles of reaction 1 can be shown as;
1 : 8 → 5 : 6
thus, 5 moles of CO₂ will form from the combustion of 1 mole of C₅H₁₂
molecular weight of CO₂ = 44 g/mol
molecular weight of C₅H₁₂ = 72 g/mol
mass of C₅H₁₂ = 320 g
number of moles of C₅H₁₂ = mass ÷ molecular weight = 320 / 72 = 4.44 moles
thus, number of moles of CO₂ formed = 5 * 4.44 = 22.2 moles
mass of CO₂ formed = 22.2* 44 = 976.8 g
The person above me is correct