KCl is neutral because KOH is a strong base and HCl is a strong acid
To determine if the salt is neutral, acidic or basic, determine how the salt was made, or from which acid and base it was derived. Once we have determined how the salt was made, determine if the acid and base are both strong, weak or one of each. If both are strong (e.g. NaOH + HCl), then the salt (NaCl) is NEUTRAL. If the base is strong and the acid is weak (KOH + HCN), then the salt (KCN) is BASIC. IF the base is weak and the acid is strong (NH3 + HCl), then the salt (NH4Cl) is ACIDIC. If both the base and the acid are weak (NH3 + CH3COOH), then then salt (CH3COONH4) will have a pH determined by which is stronger (the acid or the base) and this will depend on the Ka of the weak acid compared to the Kb of the weak base.
KCl is neutral because KOH is a strong base and HCl is a strong acid NaCN is generally basic because NaOH is a strong base and HCN is a very week acid. NH4NO3 is usually acid because HNO3 is a strong acid and NH4OH is a week base
CH3COONH4 is exactly neutral because both NH4OH ad CH3COOH are respectively week base and week acid. Moreover, the Ka of acetic acid is exactly equal to the Kb of NH4OH
To know about strong base.
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Lead Oxide
Pb is Lead
O is Oxygen
I hope this helped
Answer:
Actually, many single-celled organisms have a structure that facilitates mobility within the cell's environment. These often take the form of flagella, thin structures that emanate from the cell wall and push into the outer environment
Explanation:
Answer:
So a compound is 52% Zinc(Zn), 9.6% Carbon(C), and 38.4% Oxygen (O). Let’s first start off by assuming that we have 100 g of this compound. This means that we have 52 g of Zinc, 9.6 g of Carbon, and 38.4 g of Oxygen.Zinc = 65.38 g/molCarbon = 12 g/molOxygen = 16 g/molThis means we have:52 g of Zn(1 mol Zn/65.38 g of Zn) ≈0.8 mol of Zn.9.6 g of C(1 mol C/12 g of C) = 0.8 mol of C38.4 g of O(1 mol of O/16 g of O) = 2.4 mol of O.
Explanation:
What we want to do next is divide each element by the common factor of all of them, which is 0.8. In most cases, you divide each element by the element with the least amount of moles. After we divide each by 0.8, you’ll notice you have 1 Zn, 1 C, and 3 O. This gives you the empirical formula of ZnCO3, or Zinc Carbonate.
Work is defined energy transferred from one to another.
The formula for work done is work done = force x distance
So in our problem, force is equal to 80 kg/ m / s^2 and distance is equal to 1.25 meters. So plugging in our values will give us:
work done = 80 kg/ m/ s^2 * 1.25 m
= 100.00 J is the answer.
