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Jlenok [28]
3 years ago
15

Which contributes to the polarity of a water molecule?

Chemistry
1 answer:
Verizon [17]3 years ago
6 0
It’s molecular shape.

When the two hydrogen atoms bond with the oxygen, they attach to the top of the molecule rather like Mickey Mouse ears. This molecular structure gives the water molecule polarity, or a lopsided electrical charge that attracts other atoms. The end of the molecule with the two hydrogen atoms is positively charged.
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agasfer [191]

Answer:

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8 0
3 years ago
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How many moles of H2 can be made from complete reaction of 3.0 moles of Al?
tresset_1 [31]

Answer: 4.5 moles of H_{2} can be made from complete reaction of 3.0 moles of Al.

Explanation:

The given reaction equation is as follows.

2Al + 6HCl \rightarrow 2AlCl_{3} + 3H_{2}

This shows that 2 moles of Al reacts with 6 moles of HCl. So, the amount of HCl required to react with 1 mole Al is three times the amount of HCl.

Therefore, 3 moles of Al will react with 9 moles of HCl to give 3 moles of AlCl_{3} and \frac{9}{2} moles of H_{2}.

The reaction equation now will be as follows.

3Al + 9HCl \rightarrow 3AlCl_{3} + \frac{9}{2}H_{2}

The moles \frac{9}{2} can also be written as 4.5 moles.

Thus, we can conclude that 4.5 moles of H_{2} can be made from complete reaction of 3.0 moles of Al.

6 0
3 years ago
A gray whale can travelan average of 120<br> km per day as it migrates.
masha68 [24]

Explanation:

False, gray whales average 75 miles per day at a speed of 5 mph and is the longest annual migration of any mammal.

8 0
3 years ago
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A 10.0 mL sample of 0.25 M NaOH(aq) is titrated with 0.10 M HCl(aq) (adding HCl to NaOH). Determine which region on the titratio
Anna11 [10]

Answer:

1) After adding 15.0 mL of the HCl solution, the mixture is before the equivalence point on the titration curve.

2) The pH of the solution after adding HCl is 12.6

Explanation:

10.0 mL of 0.25 M NaOH(aq) react with 15.0 mL of 0.10 M HCl(aq). Let's calculate the moles of each reactant.

nNaOH=\frac{0.25mol}{L} .10.0 \times 10^{-3} L=2.5 \times 10^{-3}mol

nHCl=\frac{0.10mol}{L} \times 15.0 \times 10^{-3} L=1.5 \times 10^{-3}mol

There is an excess of NaOH so the mixture is before the equivalence point. When HCl completely reacts, we can calculate the moles in excess of NaOH.

                    NaOH       +       HCl       ⇒       NaCl      +         H₂O

Initial          2.5 × 10⁻³         1.5 × 10⁻³               0                      0

Reaction    -1.5 × 10⁻³        -1.5 × 10⁻³          1.5 × 10⁻³          1.5 × 10⁻³

Final            1.0 × 10⁻³               0                 1.5 × 10⁻³          1.5 × 10⁻³

The concentration of NaOH is:

[NaOH]=\frac{1.0 \times 10^{-3} mol }{25.0 \times 10^{-3} L} =0.040M

NaOH is a strong base so [OH⁻] = [NaOH].

Finally, we can calculate pOH and pH.

pOH = -log [OH⁻] = -log 0.040 = 1.4

pH = 14 - pOH = 14 - 1.4 = 12.6

5 0
3 years ago
Which determine the charge of an atom?
Andre45 [30]

Answer:

the answer is B its the number of protons and neutrons

8 0
3 years ago
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