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3 years ago

-6x+4y=-12 in slope intercept form

2 answers:

7 0

Slope intercept form is y=Mx+b
First add 6x to each side
Then you get 4y=6x-12
Next divide each side by 4 to get y alone.
Then you get y= 6/4x-3.

cricket20 [7]3 years ago

5 0

Answer:

x= 2 /3 y+2

Step-by-step explanation:

Let's solve for x.

−6x+4y=−12

Step 1: Add -4y to both sides.

−6x+4y+−4y=−12+−4y

−6x=−4y−12

Step 2: Divide both sides by -6.

−6x /−6 = −4y−12 /−6 x= 2 /3 y

=x= 2 /3 y+2

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12x + 8 + 84 = 15х +9

RideAnS [48]

Answer:

x = 83/3.

Step-by-step explanation:

12x + 8 + 84 = 15х +9

Solving for x:

8 + 84 - 9 = 15x - 12x

83 = 3x

x = 83/3.

3 0

3 years ago

Read 2 more answers

The legs of a right triangle are x and 15 while the hypotenuse is 17.

Deffense [45]

Answer:

Since the Option of equation are not given. Kindly chose any of the below equation from the answer to find the value of 'x'.

$x^2+15^2=17^2$

$x^2=17^2-15^2$

$x^2+225=289$

$x^2=289-225$

Step-by-step explanation:

Given:

Length of One leg = x

Length of other Leg= 15

Hypotenuse = 17

We need to find the equation used to determine the value of x.

Solution:

Assuming Triangle to right angled triangle.

So we will apply Pythagoras theorem which sates that;

"The square of sum of two legs of right angle triangle is equal to square of the length of hypotenuse."

so we can say that;

$x^2+15^2=17^2$

$x^2=17^2-15^2$

$x^2+225=289$

$x^2=289-225$

Since the equation are not given. Kindly chose any of the below equation from the answer to find the value of 'x'.

$x^2+15^2=17^2$

$x^2=17^2-15^2$

$x^2+225=289$

$x^2=289-225$

5 0

3 years ago

The parabolic arch of a bridge over a one-way road can be described by the equation y = -x^2 + 6, where x and y ar emeasured in

Vladimir [108]

So check the picture below

if we check the solutions or zeros for the equation, we get $\bf y=-x^2+6\implies 0=-x^2+6\implies x=\pm \sqrt{6}$

and as you can see in the picture, the value of "x" when y = 3.5, or the height of the truck is $\bf y=-x^2+6\implies 3.5=-x^2+6\implies x=\pm \sqrt{2.5}$

the truck, ends up with a clearance of $\bf \sqrt{2.5}-1.5$ on either side, so, the maximum clearance, the truck can have, those two clearances added together, $\bf 2(\sqrt{2.5}-1.5)$