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tresset_1 [31]
2 years ago
15

Which is a dominant trait that Mendel observed in pea plants?

Chemistry
2 answers:
zavuch27 [327]2 years ago
7 0

Answer:

yellow seeds

Explanation:

Arte-miy333 [17]2 years ago
5 0

Answer:

Yellow seeds

Explanation:

Dominant traits are those that are inherited unchanged in a hybridization like the yellow seeds.

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Iron has the chemical formula Fe from its Latin name, ferrum. Its atomic number is 26, and its molar mass is 55.845 grams per mole. It has a metallic gray color and is attracted to magnets. Iron is the second most-abundant metal on Earth.

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How does the periodic table help I’m predicting the formula of a stable ionic compound
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Choose whether the statements about oil sands are true or false. The viscosity of bitumen is about 100 times greater than the vi
Alexxx [7]

The First 2 statements stated above were false whereas the third one is a true statement.

Explanation:

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Reason - The viscosity of bitumen is about not 100 times greater than the viscosity of water, it is actually 100, 000 times greater.

  • Oil from oil sand deposits is only obtained by first heating the sands at high temperatures is False.

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6 0
3 years ago
Molecules are likely to dissolve in nonpolar solvents.
masha68 [24]
The answer to this is yes they are likely, true.
4 0
2 years ago
Calculate the standard entropy change for the following reactions at 25°C.
Art [367]

Answer:

(a) ΔSº = 216.10 J/K

(b) ΔSº = - 56.4 J/K

(c) ΔSº = 273.8 J/K

Explanation:

We know the standard entropy change for a given reaction is given by the sum of the entropies of the products minus the entropies of reactants.

First we need to find in an appropiate reference table the standard  molar entropies entropies, and then do the calculations.

(a)        C2H5OH(l)          +        3 O2(g)         ⇒        2 CO2(g)     +    3 H2O(g)

Sº            159.9                          205.2                         213.8                  188.8

(J/Kmol)

ΔSº = [ 2(213.8) + 3(188.8) ]   - [ 159.9  + 3(205.) ]  J/K

ΔSº = 216.10 J/K

(b)         CS2(l)               +         3 O2(g)               ⇒      CO2(g)      +      2 SO2(g)

Sº          151.0                              205.2                         213.8                 248.2

(J/Kmol)

ΔSº  = [ 213.8 + 2(248.2) ] - [ 151.0 + 3(205.2) ] J/K = - 56.4 J/K

(c)        2 C6H6(l)           +        15 O2(g)                     12 CO2(g)     +     6 H2O(g)

Sº           173.3                           205.2                           213.8                    188.8

(J/Kmol)  

ΔSº  = [ 12(213.8) + 6(188.8) ] - [ 2(173.3) + 15( 205.2) ] = 273.8 J/K

Whenever possible we should always verify if our answer makes sense. Note that the signs for the entropy change agree with the change in mol gas. For example in reaction (b) we are going from 4  total mol gas reactants to 3, so the entropy change will be negative.

Note we need to multiply the entropies of each substance by  its coefficient in the balanced chemical equation.

5 0
3 years ago
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