1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Goshia [24]
2 years ago
12

If a 100. -g sample of a hydrated compound contains 37.07-g sodium, 48.39-g carbonate and 14.54-g water, find the empirical form

ula
Chemistry
1 answer:
Mumz [18]2 years ago
3 0

he required empirical formula based on the data provided is Na2CO3.H2O.

<h3>What is empirical formula?</h3>

The term empirical formula refers to the formula of a compound which shows the ratio of each specie present.

We have the following;

Mass of sodium = 37.07-g

Mass of carbonate = 48.39 g

Mass of water = 14.54-g

Number of moles of sodium = 37.07-g/23 g/mol = 2 moles

Number of moles of carbonate = 48.39 g/61 g/mol = 1 mole

Number of moles of water = 14.54/18 g/mol = 1 mole

The mole ratio is 2 : 1: 1

Hence, the required empirical formula is Na2CO3.H2O

Learn more about empirical formula : brainly.com/question/11588623

You might be interested in
Keesha performed a chemical reaction and the products looked quite different from the reactants. She knew the amount of matter h
lakkis [162]

Answer:

the spotlight effect.

Explanation:

The spotlight effect is a tendency to think that people get noticed more often than they really do. It is an overestimation of the situation regarding the concern of getting observed. It concerns the self-confidence of an individual. For example, an individual feels that everybody in a party would notice him for a bad pair of shoes while in reality, it does not concern them.

As per the question, the overestimation of people's reaction is known as the spotlight effect.

5 0
3 years ago
Read the passage below and choose the best answer for the main idea of the passage:
Crank

Answer: C

Explanation:

4 0
3 years ago
How many moles of na2co3 are necessary to reach stoichiometric quantities with cacl2
lbvjy [14]

0.0102 moles Na₂CO₃ = 1.08g of Na₂CO₃ is necessary  to reach stoichiometric quantities with cacl2.

<h3>Explanation:</h3>

Based on the reaction

CaCl₂ + Na₂CO₃ → 2NaCl + CaCO₃

1 mole of CaCl₂ reacts per mole of Na₂CO₃

we have to calculate how many moles of CaCl2•2H2O are present in 1.50 g

  • We must calculate the moles of CaCl2•2H2O using its molar mass (147.0146g/mol) in order to answer this issue.
  • These moles, which are equal to moles of CaCl2 and moles of Na2CO3, are required to obtain stoichiometric amounts.
  • Then, we must use the molar mass of Na2CO3 (105.99g/mol) to determine the mass:

<h3>Moles CaCl₂.2H₂O:</h3>

1.50g * (1mol / 147.0146g) = 0.0102 moles CaCl₂.2H₂O = 0.0102moles CaCl₂

Moles Na₂CO₃:

0.0102 moles Na₂CO₃

Mass Na₂CO₃:

0.0102 moles * (105.99g / mol) = 1.08g of Na₂CO₃ are present

Therefore, we can conclude that 0.0102 moles Na₂CO₃  is necessary.to reach stoichiometric quantities with cacl2.

To learn more about stoichiometric quantities visit:

<h3>brainly.com/question/28174111</h3>

#SPJ4

7 0
2 years ago
A student calculated that the amount of NaCl that should form in the lab (theoretical yield) is 2.50 grams. The actual amount fo
Kitty [74]
0.92%. student calculated that the amount of NaCl that should form in the lab
3 0
3 years ago
how many grams of molecular oxygen (O2) is produced from 13.8 grams of calcium chlorate (Ca(ClO3)2)in the following chemical rea
olga2289 [7]

Answer:

6.72 g

Explanation:

Given data:

Mass of calcium chlorate = 13.8 g

Mass of oxygen produced = ?

Solution:

Chemical equation:

Ca(ClO₃)₂        →      CaCl₂ + 3O₂

Number of moles of calcium chlorate:

Number of moles = mass / molar mass

Number of moles = 13.8 g/ 206.98 g/mol

Number of moles = 0.07 mol

Now we will compare the moles of oxygen and  calcium chlorate.

                 Ca(ClO₃)₂         :            O₂

                      1                   :              3

                    0.07               :            3×0.07=0.21 mol

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 0.21 mol × 32 g/mol

Mass = 6.72 g

3 0
3 years ago
Other questions:
  • Jeff used an equal arm balance to weigh a 4.312 g sample of sodium chloride. Which of these measurements made by Jeff is the mos
    14·2 answers
  • A 45 gram piece of metal has a volume of 18cm3. What is the density of this metal?
    10·1 answer
  • HELPPPPPPPPPPPPP ME PLSSSSSSSSSSS
    7·1 answer
  • A student will measure and record the growth of two flowering plants every day for 28 days. Plant A will be watered and fertiliz
    6·1 answer
  • Why are frogs said to have two lives
    15·2 answers
  • How many Cl atoms are in Zn(ClO3)2?<br> O A. 2<br> O B. 1<br> O c. 3<br> O D. 6
    10·1 answer
  • Which terms correctly identify the indicated structures in this sketch of a cell viewed under a microscope? Match each label to
    15·1 answer
  • 17. A substance breaks down into its component elements when it is heated. If 68.0 g of
    11·1 answer
  • If I have a +2 oxidation number do I give up or accept electrons?​
    8·1 answer
  • 2. In which state of matter do particles vibrate in place? *
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!