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olya-2409 [2.1K]
3 years ago
14

Help help help help help help help help

Mathematics
1 answer:
Leya [2.2K]3 years ago
8 0

Answer:

first off, take pic right side up next time. secondly, it's the forth one down

Step-by-step explanation:

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what are the first 5 common multiples of 14 and 20? i’ll mark brainliest for whoever answers first!!!
shutvik [7]

Answer:

14, 28, 42, 56, and 70 are the first 5 common multiples of 14

20, 40, 60, 80, and 100 are the first 4 common multiples of 20

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Pls show full working out
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Answer:

  • Question 1a. i) x=1.8m

  • Question 1a. ii)   Volume=27.6m^3

  • Question 1b) Volume=65.9m^3

Explanation:

<u><em>Question 1 a. i) Find the value of x.</em></u>

         tan(\theta )=\dfrac{opposite\text{ }leg}{adjacent\text{ }leg}

For the smalll triangle you can write:

        tan(\theta )=\dfrac{x}{1m}

For tthe big triangle:

      tan(\theta )=\dfrac{x+2.7m}{2.5m}

Substitute:

        \dfrac{x}{1m}=\dfrac{x+2.7m}{2.5m}

Solve for x:

        2.5x=x+2.7m\\\\2.5x-x=2.7m\\\\1.5x=2.7m\\\\x=2.7m/1.5\\\\x=1.8m

<u><em>Question 1a ii) Find the volume of the frustrum</em></u>

  • Find the volume of a cone with height = 2.7m + 1.8m = 4.5m, and radius = 2.5m

Formula:

         Volume=(1/3)\pi \times radius^2\times height

Substitute:

         Volume=(1/3)\pi \times (2.5m)^2\times 4.5m=9.375\pi m^3

  • Find the volume of a cone with heigth = 1.8m and radius = 1m

        Volume=(1/3)\pi \times (1m)^2\times 1.8m=0.6\pi m^3

  • Subtract the volume of the small cone from the volume of the big cone

        Volume\text{ }of\text{ }frustrum=9.375\pi m^3-0.6\pi m^3=8.775\pi m^3\approx 27.6m^3

<u><em>Question 1b. Calculate the volume of the bin</em></u>

<u>i) Upper frustrum</u>

This is the same frustrum from the equation of above, thus ist volume is 27.6m³.

<u>ii) Lower frustrum</u>

            \dfrac{x}{2.0m}=\dfrac{x+2.4m}{2.5m}

           2.5x=2(x+2.4m)\\\\2.5x=2x+4.8m\\\\0.5x=4.8m\\\\x=9.6m

        Volume=(1/3)\pi \times (2.5m)^2\times (9.6m+2.4m)-(2.0m)^2\times (9.6m)

       Volume=38.3m^3

<u>iii) Add the volume of the two frustrums</u>

  • Volume=27.6m^3+38.3m^3=65.9m^3

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The minimum and maximum temperatures in the house are 68.5°F and 76.5°.
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Michael draws three parallelograms. In each figure, he measures a pair of angles, as shown.
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we know that

In parallelogram, the sum of consecutive angles are 180

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And opposite angles are equal

so, we will check verify each options

option-A:

Since, consecutive angles are supplementary

so, this is FALSE

option-B:

Since, only opposite angles are equal or congruent

so, this is FALSE

option-C:

Since, consecutive angles are supplementary

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option-D:

Since, consecutive angles are supplementary

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