C. The design would not be cost-efficient; the plane would require more fuel due to increased thrust from higher drag.
Find the [OH-] in the solution. The pH is 9.5, so the pOH is 14 - 9.5 = 4.5.
[OH-] = 10^-4.5 M
Now use the dilution equation to find the new [OH-] after the volume is reduced from 150 mL to 50 mL:
M1V1 = M2V2
M1 = 10^-4.5 M
V1 = 150 mL
M2 = ?
V2 = 50 mL
(10^-4.5)(150) = M2(50)
M2 = 9.5 x 10^-5 M ≈ 1 • 10^-4 (We can only use one sig fig, because the pH was given to one decimal place.)
Now use this [OH-] to find pOH:
pOH = -log(1 x 10^-4) = 4.0
14 - pOH = pH, so the expected pH for the new solution is 10.
Answer:
138.39 g/mol
Explanation:
Formula mass is a synonym for molar mass, which is the sum of all the masses of the elements. These can be found on a periodic table.
Because this is hydrated, the formula needs to include H2O.
MgSO4 + H2O
Mg + S + 4O + 2H + O
24.31 + 32.07 + (4*16) + (2*1.008) + 16 = about <u>138.39</u>
