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2 years ago

What pressure will be exerted by 0.650 mol of a gas at 30.0C if it is contained in a 0.700 L vessel?

1 answer:

8 0

I believe you need to use the ideal gas constant which is Pv=nRT and P is the pressure so if you solve for P you get P=(nRT)/v and you can then just plug in n= number of moles T=temp in kelvins v=volume in liters R= is a constant of .08206 L*atm/K*mol

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pishuonlain [190]

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There will be formed 39.1935 grams H2O formed

Explanation:

Step 1: The balanced equation

2H2 + 02 → 2H20

Step 2: Given data

mass of hydrogen = 14.8 grams

Molar mass of hydrogen = 2.02 g/mole

mass of oxygen = 34.8 grams

Molar mass of oxygen = 32 g/mole

Step 3: Calculate moles

moles = mass / Molar mass

moles of hydrogen = 14.8g/ 2.02 g/mole = 7.33 moles

moles of oxygen = 34.8g / 32g/mole = 1.0875 moles

For 2 moles hydrogen consumed, we need 1 mole of oxygen.

This means oxygen is the limiting reagens and will be consumed completely. Hydrogen is the reactant in excess, there will remain 5.155 moles of hydrogen

Step 4: Calculate moles of H2O

We see that for 2 moles of H2 consumed, there is needed 1 mole of O2, to produce 2 moles of H2O.

For 1.0875 moles of oxygen consumed, there will be produced 2.175 moles of H2O

Step 5: Calculate mass of water

Mass of H2O = moles of H2O * Molar mass of H2O

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There will be formed 39.1935 grams H2O formed

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