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3 years ago

What pressure will be exerted by 0.650 mol of a gas at 30.0C if it is contained in a 0.700 L vessel?

1 answer:

8 0

I believe you need to use the ideal gas constant which is Pv=nRT and P is the pressure so if you solve for P you get P=(nRT)/v and you can then just plug in n= number of moles T=temp in kelvins v=volume in liters R= is a constant of .08206 L*atm/K*mol

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Answer:

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3 years ago

Why does summer receive more daylight hours than winter

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For a titration of 25 ml of naoh solution, 23.30 ml of hcl solution if used. what is the molarity of naoh

Eduardwww [97]

HCl(aq)+NaOH(aq)→NaCl(aq)+H2O(l)

As you can see here, one mole of acid neutralizes one mole of base.

We use the concentration equation, which states that,

c=nv

n is the number of moles v is the volume of solution

Rearranging for moles, we get,

n=c⋅v

So, we have:

nNaOH=0.1 M⋅0.05 L

=0.005 mol

Since one mole of acid neutralizes one mole of base, then we must have: nHCl=nNaOH.

And so,

cHCl=nHClvHCl

=0.005 mol0.03 L

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3 0

3 years ago

If 200 g of benzoyl peroxide are used with 38 Kg of PTFE monomer, calculate the expected molecular weight of the polymer if (i)

den301095 [7]

Explanation:

The molecular weight of benzoyl peroxide is 242.23 g/mol.

Therefore, number of moles present in 200 g of benzoyl peroxide are as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{200 g}{242.23 g/mol}$

= 0.825 mol

Molecular weight of PTFE is 100 g/mol.Hence, calculate the number of moles of PTFE in 38 kg as follows.

As 1 kg = 1000 g. So, 38 kg = 38000 g.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{38000 g}{100 g/mol}$

= 380 mol

As it is given that the initiator is 15% active. So, actual number of moles of benzoyl peroxide are as follows.

$0.15 \times 0.826$

= 0.124 mol

For combination, 1 mol of benzoyl peroxide produces 1 chain. Therefore, degree of polymerization will be calculated as follows.

DP = $\frac{380 mol}{0.124 mol}$

= 3065.33 mol

Average molecular weight of monomer is as follows.

$\frac{0.124}{0.124 + 380} \times MW_{benzoyl} + \frac{380}{0.124 + 380} \times MW_{PTFE}$

= 100.05 g/mol

Therefore, calculate the expected molecular weight of polymer as follows.

$3065.33 \times 100.05 g/mol$

= 306675.23 g/mol

Hence, for disproportion 1 mole benzoyl peroxide produces 2 chains.

DP = $\frac{2 \times 380}{0.124}$

= 6129.03

Therefore, calculate the expected polymer weight as follows.

$6129.03 \times 100.05$

= 613209.68 g/mol

Thus, we can conclude that the the expected polymer weight is 613209.68 g/mol.

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