What pressure will be exerted by 0.650 mol of a gas at 30.0C if it is contained in a 0.700 L vessel?

1 answer:

8 0

I believe you need to use the ideal gas constant which is Pv=nRT and P is the pressure so if you solve for P you get P=(nRT)/v and you can then just plug in n= number of moles T=temp in kelvins v=volume in liters R= is a constant of .08206 L*atm/K*mol

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Explain reaction of metals with the following with the help of chemical equations. i) with acids ii) with oxygen iii) with water

Amiraneli [1.4K]

i. When an acid reacts with metal, a salt and hydrogen are produced:

ii. When oxygen and metal react, metal oxide forms also known as rust

iii. metal and water produce hydrogen gas

6 0

3 years ago

Anyone have any idea what to do

ra1l [238]

Answer:

2Al+3Fe ------- Al2O3+3Fe

this is answer no 2

N2+3H2------- 2NH3

this is answer no 3

I think helps

Best of luck

4 0

2 years ago

What is the ph of a solution labeled .30 trimethylamine k for trimethylamine is 7.42 x 10^4

valentina_108 [34]

Answer:the pH is 12

Explanation:

First We need to understand the structure of trimethylamine

Due to the grades of the bond in the nitrogen with a hybridization sp3 is 108° approximately, then is generated a dipole magnetic at the upper side of the nitrogen, this dipole magnetic going to attract a hydrogen molecule of the water making the water more alkaline

C3H9N+ H2O --> C3H9NH + OH-

$k=\frac{[C3H9NH]*[OH-]}{[C3H9N]}$

Then:

The concentration of the trimethylamine is 0.3 and the concentration of the ion C3H9NH is equal to the OH- relying on the stoichiometric equation. We could find the concentration of the OH- ion with the square root of the multiplication between k and the concentration of trimethylamine

[OH-]= $\sqrt{ 0.3*7.42x10^{-4}}$