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xenn [34]
3 years ago
11

Name and find the measure of each angle in the figure. HELP PLEASE

Mathematics
1 answer:
stich3 [128]3 years ago
4 0
Is the algebra, if so what type?
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You start at (2, -4). You move up 4 units. Where do you end?​
NeTakaya

Answer:

(2, 0)

Step-by-step explanation:

Hope This Helps! : )

7 0
3 years ago
Need answer ASAP<br><br><br><br><br> Express a 10/3 b 7/3 in simplified radical form.
anastassius [24]
I guess this is what you mean     3√a^10      and 3√b^7
5 0
2 years ago
Find the missing value of x and y.
scoray [572]

Step-by-step explanation:

tan 60 = 21 ÷ y

1.73 = 21 ÷ y

y = 21 ÷ 1.73

y = 12.14

tan 30 = x÷ 12

0.6 x 12 = x

x = 7.2

4 0
3 years ago
A source of laser light sends rays AB and AC toward two opposite walls of a hall. The light rays strike the walls at points B an
Nataly [62]

Answer:

The distance between the walls is 70 m.

Step-by-step explanation:

Given: A source of laser light is at point A on the ground between two parallel walls BE and CD . The walls are perpendicular to the ground that is

BE ⊥ ED and CD ⊥ ED

AB is a ray of light which strikes the wall on the left at point B which is 30 meters above the ground. that is BE = 30 m

AC is a ray of light which strikes the wall on the right at point C. The length of AC = 80 meters.

The ray AB makes an angle of 45 degrees with the ground that is m∠BAE = 45°

The ray AC makes an angle of 60 degrees with the ground that is m∠CAD = 60°

As shown is figure attached below.

WE have to find the distance between the walls that is Length of ED

Length of ED = EA + AD

Consider the Δ AEB,

Using trigonometric ratio,

\tan\theta=\frac{perpendicular}{base}

Here \theta=45^{\circ} , perpendicular = 30 m  and base we can find.

thus,

\tan 45^{\circ}=\frac{30}{EA}

We know \tan 45^{\circ}=1

thus, EA =  30 m

Consider the Δ AEB,

Using trigonometric ratio,

\cos\theta=\frac{base}{hypotenuse}

Here \theta=60^{\circ} , hypotenuse = 80 m  and base we can find.

thus, \cos 60^{\circ}=\frac{base}{80}

We know, \cos 60^{\circ}=\frac{1}{2}

thus, Base = 40 m

AD = 40 m

Thus, the distance between the walls that is the length of ED = 30 + 40 = 70 m

4 0
3 years ago
If f(x) = -x + 5 and g(x) = x^2, what is (g*f)(-1)
sasho [114]

Answer:

6

Step-by-step explanation:

(g × f)(x) = g(x) × f(x) = x²(- x + 5)

To evaluate (g × f)(- 1) substitute x = - 1 into the product

x²(- x + 5)

= (- 1)²(- (- 1) + 5)

= 1(1 + 5)

= 1 × 6 = 6

5 0
3 years ago
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