Question

A delivery process has a target of 5 hours plus or minus one hour. The process standard deviation is estimated as 0.24 hours. The process has a ____ sigma quality level.

Answer 1

Answer:

the sigma quality level is 8.33

Step-by-step explanation:

given the data in the question;

Target of a delivery process = 5 hours plus or minus one hour i.e 5 ± 1

standard deviation of the process σ = 0.24 hours.

so,

The Lower Limit $L_L$ of the target will be;

$L_L$ = 5 hours - 1 hours = 4 hours

And the Upper Limit $U_L$ of the target will be;

$U_L$ = 5 hours + 1 hours = 6 hours

sigma quality level = ?

Now, to get the sigma quality level, we use the following expression;

sigma quality level = ( Upper Limit $U_L$ of the target - Lower Limit $L_L$ of the target ) / standard deviation of the process

sigma quality level = ( $U_L$ - $L_L$ ) / σ

so we substitute in our values

sigma quality level = ( 6 - 4 ) / 0.24

sigma quality level = 2 / 0.24

sigma quality level = 8.33

Therefore, the sigma quality level is 8.33